To determine how many times 4 goes into 1024, you would divide 1024 by 4. The result is 256, meaning that 4 goes into 1024 exactly 256 times. This is because 4 multiplied by 256 equals 1024.
To find out how many times 2 goes into 1024, you would perform the division 1024 รท 2. The result is 512, meaning that 2 goes into 1024 a total of 512 times without any remainder. This is because 1024 is a power of 2 (2^10), so it is evenly divisible by 2.
Apply Euclid's Division Lemma(or in simple words Division Algorithm) to 1024 and 181: 1024 = 181 x 5 + 119 181 goes 5 times into 1024 with remainder 119. It means if we subtract 1024 from the 6th multiple of 181 then we get the required which is to be added to 1024. Way of obtaining 6th multiple: (This method is useful when we deal with large numbers!) If we subtract 119 from 1024 then we get 5th multiple of 181. 1024 - 119 = 905. And on adding 181 to 905 we get the 6th multiple of 181. 181 + 905 = 1086. And 1086 - 1024 = 64 is the required number.
Every number from 1 to 114 goes into 343 at least three times. There is no number that goes into 343 three times evenly, with no remainder.
Five is a prime number, so no whole number (other than 1) can go into it evenly. However, 2.5 goes into 5 twice, and 1.25 goes into 5 four times.
560 goes into 2800 five times.
To determine how many times 4 goes into 1024, you would divide 1024 by 4. The result is 256, meaning that 4 goes into 1024 exactly 256 times. This is because 4 multiplied by 256 equals 1024.
Five times 25 --> 25
To find out how many times 2 goes into 1024, you would perform the division 1024 รท 2. The result is 512, meaning that 2 goes into 1024 a total of 512 times without any remainder. This is because 1024 is a power of 2 (2^10), so it is evenly divisible by 2.
the answer is five. 60 goes into 300 five times.
Apply Euclid's Division Lemma(or in simple words Division Algorithm) to 1024 and 181: 1024 = 181 x 5 + 119 181 goes 5 times into 1024 with remainder 119. It means if we subtract 1024 from the 6th multiple of 181 then we get the required which is to be added to 1024. Way of obtaining 6th multiple: (This method is useful when we deal with large numbers!) If we subtract 119 from 1024 then we get 5th multiple of 181. 1024 - 119 = 905. And on adding 181 to 905 we get the 6th multiple of 181. 181 + 905 = 1086. And 1086 - 1024 = 64 is the required number.
First, you find a number that goes into both 12 and 30. This number is two. Two goes into 12, six times and 30, fifteen times. So now you have to find a number that goes into both six and fifteen. This number is 3. Three goes into six two times and fifteen five times. There is no number that can go into 2 & 5 besides one. So two fifths (2/5) is your simplified fraction. or two over five.
if the space is between 256 and 16, 64 goes in there.
15 goes into 75 five times
ten goes into five 10000000 times
Four goes into twenty five times.
The number is 1.