35
if 35 isn't what you were wandering but the name of 1,010,111,111,111,111,111 is the i would say it's a little over a googleplex.
1991
215
215
35
Write 87 tens and 2 ones as a base ten number.
8 tens 2 ones
96
539 tens and 2 ones
254 - has 2 hundreds, 5 tens, and 4 ones
The first (left most) digit is the number of tens and the other is the number of ones. So 57 = 5 tens plus 7 ones = 50 + 7 = 57
62
32
The number you are looking for is 74.
52
There is no four digit number where the ones is twice the tens, the hundreds is five less than the ones, and the thousands is the sum of the tens and hundreds. int ones, tens, hundreds, thousands; for (thousands=1; thousands<10; thousands++) { /**/ for (hundreds=0; hundreds<10; hundreds++) { /**/ /**/ for (tens=0; tens<10; tens++) { /**/ /**/ /**/ for (ones=0; ones<10; ones++) { /**/ /**/ /**/ /**/ if (ones != 2 * tens) break; /**/ /**/ /**/ /**/ if (hundreds != ones - 5) break; /**/ /**/ /**/ /**/ if (thousands != tens + hundreds) break; /**/ /**/ /**/ /**/ printf ("dd\n", thousands, hundreds, tens, ones); /**/ /**/ /**/ } /**/ /**/ } /**/ } }
752