Well, honey, the smallest number divisible by 2, 3, 5, and 9 is 90. It's like finding a unicorn in a field of horses - rare but not impossible. So, there you have it, 90 is the magic number that can be divided by all those divas.
Well, isn't that just a happy little question! To find a number that is divisible by 2, 3, 5, and 9, we can look for the least common multiple of these numbers. In this case, the least common multiple of 2, 3, 5, and 9 is 90. So, any multiple of 90 will be divisible by 2, 3, 5, and 9.
Since 5232 is divisible by both 2 and 3, it is divisible by 6.A number must be divisible by both 2 and 3 to be divisible by 6.The number 5232 is even, so it is divisible by 2.If you add the individual digits in the number (5+2+3+2=12) you get a number that is divisible by 3, meaning the original number (5232) is also divisible by 3.
There are no numbers that satisfy this. If a number is divisible by both 2 and 5, then it must also be divisible by 10.
To determine if a number is divisible by another number, you need to check if the first number can be divided by the second number without leaving a remainder. For 501105: Divisibility by 2: A number is divisible by 2 if its last digit is even. The last digit of 501105 is 5, which is odd, so 501105 is not divisible by 2. Divisibility by 3: A number is divisible by 3 if the sum of its digits is divisible by 3. The sum of the digits of 501105 is 5+0+1+1+0+5=12, which is divisible by 3, so 501105 is divisible by 3. Divisibility by 5: A number is divisible by 5 if its last digit is 0 or 5. The last digit of 501105 is 5, so 501105 is divisible by 5. Divisibility by 9: A number is divisible by 9 if the sum of its digits is divisible by 9. The sum of the digits of 501105 is 12, which is not divisible by 9, so 501105 is not divisible by 9. Divisibility by 10: A number is divisible by 10 if its last digit is 0. The last digit of 501105 is 5, so 501105 is not divisible by 10.
A number that is divisible by 2, 3, 4, 5, and 10 must be divisible by the least common multiple of these numbers, which is 60. Therefore, any number that is a multiple of 60 will be divisible by 2, 3, 4, 5, and 10. This is because 60 is the smallest number that contains all the prime factors of 2, 3, 4, 5, and 10.
To determine if a number is divisible by 6, it must be divisible by both 2 and 3. To determine if a number is divisible by 2, it should be even - in other words, it should end with 0, 2, 4, 6, or 8. To determine if a number is divisible by 3, the sum of its digits should be divisible by 3. 54,132 is an even number, so it is divisible by 2. 5 + 4 + 1 + 3 + 2 = 15, which is divisible by 3, so 54,132 is divisible by 3. Since 54,132 is divisible by both 2 and 3, it is divisible by 6.
30 is divisible by, and is the least common multiple of, 2, 3, and 5.
Since 5232 is divisible by both 2 and 3, it is divisible by 6.A number must be divisible by both 2 and 3 to be divisible by 6.The number 5232 is even, so it is divisible by 2.If you add the individual digits in the number (5+2+3+2=12) you get a number that is divisible by 3, meaning the original number (5232) is also divisible by 3.
Is 5225 divisible by 3? A number is divisible by 3, if the sum of its digits is evenly divisible by 3. 5 + 2 + 2 + 5 = 14. Since 14 is not divisible by 3, neither is 5225.
The greatest 3-digit number that is not divisible by 2, 3, 5, or 10 is 997.
If you want your answer to be a whole number, it is divisible by 2 and 5.
There are no numbers that satisfy this. If a number is divisible by both 2 and 5, then it must also be divisible by 10.
There is none. Any number that is divisible by 2 and 5, for example, must also be divisible by 10.
30
no.. heres a trick: if you add together the numbers (5+2+4) and that answer equals a number that is divisible by 3 then the number is divisible by three 5+2+4=11 11 is not divisible by 3 therefore, 524 is not divisible by 3
Of 2, 3, 4, 5, and 8, the smallest number divisible by 2 is 2.
No, just 2, 3 and 5.
A number that is divisible by 15 is divisible both by 5 and 3 A number is divisible by 5 if it ends with 0 or 5 A number is divisible by 3 if the sum of its digits is divisible by 3 e.g. 4035 is divisible by 15 as it ends with a 5 and 4+0+3+5=12 which is divisible by 3