Any number that you choose can be the next number. It is easy to find a rule based on a polynomial of order 7 such that the first seven numbers are as listed in the question followed by the chosen next number. There are also non-polynomial solutions. Short of reading the mind of the person who posed the question, there is no way of determining which of the infinitely many solutions is the "correct" one.The simplest solution, based on a polynomial of order six isU(n) = (-19*n^6 + 495*n^5 - 5080*n^4 + 25935*n^3 -68161*n^2 + 84750*n - 35160)/60 for n = 1, 2, 3, ...and accordingl, the next term is 150.
12
12
5
17?
The next number in the sequence is 15 - the sequence goes x2, +2, -1
a
10. Then 12, 14, 16, 18, 20, 22, 24, etc.
A single number, such as 4642142824816 does not constitute a sequence.
The next numbers in the sequence are... 16, then 88.
5
17?
From the given sequence, the pattern appears to be 47-42=4, 42/3=14, 14*2=28, 28-4=24, 24/3=8, 8*2=16 and therefore the next number will be 16-4=12.
15
The next number in the sequence is 15 - the sequence goes x2, +2, -1
15
92 - 18 = 72 72 - 16 = 56 56 - 14 = 42 42 - 12 = 30 30 - 10 = 20 20 is the next number in the sequence.
The next number in the sequence 2, 4, 16, 64 is 256.
16 is the next squared number.
are you sure it is not1 2 3 6 8 7 14 16because that sequence doubles for the first one, then adds two for the next number, then subtracts one for the third, then repeats. So the next number is 15.