LCM(2, 3, 4, 5, 6, 10) = 60 so the number is 61.
1098765433 will have a remainder of 1.
The remainder is always 31 or less.
No answer is possible as any number divided by 9 must either be exactly divisible by 9 or leave a remainder less than 9.
989. If there is a remainder of 2 when divided by 3, the number is one less than a multiple of 3. If there is a remainder of 4 when divided by 5, the number is one less than a multiple of 5. Thus the number required is one less than a multiple of the lowest common multiple of 3 and 5 (that is 15). So what is needed is an even multiple of 15 less than or equal to 1000: 1000 ÷ 15 = 662/3 Thus the highest even multiple of 15 not greater than 1000 is 66 x 15 = 990, and the required number is 989.
14. The largest possible number for a remainder is 1 less than the divisor.
3 divided by 2 has a remainder of 1. Which is 1 less than 2.
56
18
1098765433 will have a remainder of 1.
The remainder is always 31 or less.
24 is answer.
37 is the number.
Every 2 digit number, when divided by the number one less than it, will result in a remainder of 1.
No answer is possible as any number divided by 9 must either be exactly divisible by 9 or leave a remainder less than 9.
989. If there is a remainder of 2 when divided by 3, the number is one less than a multiple of 3. If there is a remainder of 4 when divided by 5, the number is one less than a multiple of 5. Thus the number required is one less than a multiple of the lowest common multiple of 3 and 5 (that is 15). So what is needed is an even multiple of 15 less than or equal to 1000: 1000 ÷ 15 = 662/3 Thus the highest even multiple of 15 not greater than 1000 is 66 x 15 = 990, and the required number is 989.
14. The largest possible number for a remainder is 1 less than the divisor.
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