Zero
I am an even three digit number If you round me to the nearest ten I become 200 The sum of my digets is 18 What number am I?
the answer of 2 cubed is 4 because 2x2=4
61.02x^3
N3 + 57.6+3.42
Twice divided by the cube of the sum of x and 2 is equal to 2 times the reciprocal of ((x + 2) cubed)).
I am an even three digit number If you round me to the nearest ten I become 200 The sum of my digets is 18 What number am I?
I assume you mean the sum of the digets equal 12. In that case your problem has only one solution and that is 39. No other number satisfies those criteria
If you mean the sum of two cubed numbers then the answer is simply 'none' with the trivial exception of all of them being 0. For more info check out "Fermat's last theorem".
the answer of 2 cubed is 4 because 2x2=4
n3 + 2
153 cubed is 3581577. And the sum of one number is itself.
27 2+7 = 9 X 3 = 27
19
The sum of the first n cubed numbers is the square of the nth triangular number.
61.02x^3
The sum is irrational.
N3 + 57.6+3.42