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Q: What 2 digit number if divided by 5 the remainder is 4 and both digets are odd and the sum of the digits is 10?

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0.5714

799

The answer is 1. The smallest prime is 2 and the greatest prime (of however many digits) must be odd. The remainder of ANY odd number when divided by 2 must be 1.

0.5714

I think you're wanting a number of two digits, one of which is 3, that when divided by 7 gives a quotient and a remainder of 1 and when that quotient is divided by 2 it gives a remainder of 1: Answer: 36 36 ÷ 7 = 5 r 1 5 ÷ 2 = 2 r 1 If you want the number to be such that if it is divided by 7 the remainder is 1 and if it is divided by 2 the remainder is 1, then: Answer: 43 43 ÷ 7 = 6 r 1 43 ÷ 2 = 21 r 1

Take the question apart, one step at a time. The remainder, when the number is divided by 5, is 4. That means that the ones digit is either 4 or 9. However, you know that both digits are odd, which means it has to be 9. The sum of the digits is 10, so the tens digit has to be 1. Your number is 19.

It will be 3.

5

85. A number when divided by 238, leaves a remainder 79. What will be the remainder when the number is divided bv 17 ? (1) 8 (2) 9 (3) 10 @) 11

506

No. Add the digits of the dividend and if that is divisible by 3 then the original number is divisible by 3; if not, its remainder when divided by 3 gives the remainder when the original number is divided by 3: 1 + 2 + 1 = 4 which gives a remainder of 1 when divided by 3, so 121 divided by 3 gives a remainder of 1. (121 = 40 x 3 + 1)

A number leaves reminder 6 when divided by 10. What is the remainder when the number is divided by 5? Justify your reasoning.

2519

58

59

29

57

0.6084

Any even number will not have a remainder when divided by two. Any odd number, however, will.

The number is 19.

24

209

Nine can be divided by 5 with a remainder of 4.

27

It is a factor of that number and leaves no remainder