Any number that is a multiple of both 2 and 3.
2x3=6
6x3=18
18x6=108
108x18=1944
1944x108=209952
209952x1944=408146688
2x3=6
6x2=12
12x6=72
72x12=864
864x72=62208
62208x864=53747712
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Numbers that are divisible by both 2 and 3 are multiples of their least common multiple, which is 6. Therefore, any number that is divisible by both 2 and 3 will be a multiple of 6. In other words, numbers such as 6, 12, 18, 24, and so on are divisible by both 2 and 3.
Oh, dude, numbers divisible by both 2 and 3 are multiples of their least common multiple, which is 6. So, like, any number that's a multiple of 6 will totally fit the bill. It's like hitting two birds with one stone, but in a mathy way.
between 1 and 600 inclusive there are:300 numbers divisible by 2200 numbers divisible by 3100 numbers divisible by both 2 and 3400 numbers divisible by 2 or 3.
Numbers are divisible by 6 if they are divisible by both 2 and 3.All even numbers are divisible by 2. Odd numbers are not.To see if a number is divisible by 3, add the individual digits of the number to each other and see if that number is divisible by 3. If it is, then the original number is also divisible by 3.Example: 2712, add 2+7+1+2=12 Is 12 divisible by 3? Yes. Therefore, 2712 is divisible by 3.The number 2712 is also divisible by 2, since it is an even number.Now you know that 2712 is divisible by 6.
6
No. 26 for instance the sum of the digits is 8 but not divisible by 4. 32 the sum of the digits is 5 but divisible by 4 The rules for some other numbers are 2 all even numbers are divisible by 2 3 The sum of the digits is divisible by 3 4 The last 2 numbers are divisible by 4 5 The number ends in a 0 or 5 6 The sum of the digits is divisible by 3 and is even 7 no easy method 8 The last 3 numbers are divisible by 8 9 The sum of the digits is divisible by 9
The sum of three consecutive odd numbers must be divisible by 3. As 59 is not wholly divisible by 3 the question is invalid. PROOF : Let the numbers be n - 2, n and n + 2. Then the sum is 3n which is divisible by 3. If the question refers to three consecutive numbers then a similar proof shows that the sum of these three numbers is also divisible by 3. Again, the question would be invalid.