A number is a multiple of 80 if the last 4 digits are a multiple of 80
It also works if the number is a multiple of 5 and 16 at the same time because 80 = 2^4 x 5 = 16 x 5
No; it is divisible only by its factors (1, 2, 4, 5, 8, 10, 16, 20, 40, and 80).
There are 80 such numbers.
There are: 26
between 1 and 600 inclusive there are:300 numbers divisible by 2200 numbers divisible by 3100 numbers divisible by both 2 and 3400 numbers divisible by 2 or 3.
There is an infinite number of numbers that are not divisible by seven!
Numbers that are divisible by 80 are itself and any of its other multiples
Yes and by any of its factors
No; it is divisible only by its factors (1, 2, 4, 5, 8, 10, 16, 20, 40, and 80).
101
There are 80 such numbers.
40, 80, 120... Any multiple of 40.
Numbers that are divisible by both 4 and 5 are multiples of the least common multiple of 4 and 5, which is 20. Therefore, numbers that are divisible by 4 and 5 are multiples of 20. In other words, any number that can be expressed as 20 multiplied by an integer (e.g., 20, 40, 60, 80, etc.) is divisible by both 4 and 5.
1, 2, 4, 5, 8, 10, 16, 20, 40, 80
1, 2, 4, 5, 8, 10, 16, 20, 40, 80
80%. Out of every ten numbers, one is divisible by 10, and that same one plus one moreare both divisible by 5. The remaining eight are divisible by neither 5 nor 10.
If the last 4 digits are divisible by 80, the entire number is divisible by 80.But really, it is hardly worth-while to learn divisibility rules for a large amount of numbers; only for a few small numbers. Normally it is easier to just do the division.
Both numbers are divisible by 5.