A number is a multiple of 80 if the last 4 digits are a multiple of 80
It also works if the number is a multiple of 5 and 16 at the same time because 80 = 2^4 x 5 = 16 x 5
No; it is divisible only by its factors (1, 2, 4, 5, 8, 10, 16, 20, 40, and 80).
There are: 26
There are 80 such numbers.
between 1 and 600 inclusive there are:300 numbers divisible by 2200 numbers divisible by 3100 numbers divisible by both 2 and 3400 numbers divisible by 2 or 3.
160 is divisible by all three numbers, 10, 2, and 5. 160 / 10 = 16 160 / 2 = 80 160 / 5 = 32
Numbers that are divisible by 80 are itself and any of its other multiples
Yes and by any of its factors
No; it is divisible only by its factors (1, 2, 4, 5, 8, 10, 16, 20, 40, and 80).
101
There are 80 such numbers.
There are: 26
40, 80, 120... Any multiple of 40.
1, 2, 4, 5, 8, 10, 16, 20, 40, 80
1, 2, 4, 5, 8, 10, 16, 20, 40, 80
80%. Out of every ten numbers, one is divisible by 10, and that same one plus one moreare both divisible by 5. The remaining eight are divisible by neither 5 nor 10.
If the last 4 digits are divisible by 80, the entire number is divisible by 80.But really, it is hardly worth-while to learn divisibility rules for a large amount of numbers; only for a few small numbers. Normally it is easier to just do the division.
Both numbers are divisible by 5.