Three: 1 7 49.
1, 2, 3, 6, 9, 18 1, 7, 49
Besides 49 & 98? The numbers divisible by 49 are infinite.
7*7=49 1*49=49 -7*-7=49 -1*-49=49
147 / 3 = 49 49 will be the center number, just add and subtract 2 to/from 49 and you get 47+ 49 + 51 = 147
1 and 49
1, 7, 49.
1, 7, 49.
Three: 1 7 49.
Three: 1 7 49.
The HCF of both numbers is 1
7
4 and 8
The two whole numbers that can go into 98 are 1, 2, 7, 49, and 98.
1 and 7 will go into both numbers evenly with no remainders
1, 2, 3, 6, 9, 18 1, 7, 49
49-0 in egyptian numbers = 49