1 * 56 = 56
2 * 28 = 56
4 * 14 = 56
7 * 8 = 56
8 * 7 = 56
14 * 4 = 56
28 * 2 = 56
56 * 1 = 56
The product of 8 & 7 is 56 (8x7=56)
The numbers are 56 and 57.
The two numbers with the sum of 15 and the product of 56 are: 7 + 8 = 15 7 x 8 = 56
86
The numbers are 56 and 57.
56 = 7 x 8 = 7 x 23 then 56 is not a product of 3different prime numbers
The two numbers that have a sum of 56 and a product of 56 are 28 and 28. This is because 28 + 28 equals 56, and 28 × 28 also equals 784, which doesn't match the product requirement. However, for unique pairs, the correct numbers are 8 and 7, which sum to 15, and their product is 56.
The product of 8 & 7 is 56 (8x7=56)
no
7*8=56
The numbers are 56 and 57.
The two numbers with the sum of 15 and the product of 56 are: 7 + 8 = 15 7 x 8 = 56
-56 and -1 -56+(-1)=-57 -56*(-1)=56
14x4
There is no set of odd numbers whose product is 56 since the latter is even.
No becaues as a product of its prime factors: 2*2*2*7 = 56 or as 23*7 = 56
No because as a product of its prime factors: 2*2*2*7 = 56