1 * 56 = 56
2 * 28 = 56
4 * 14 = 56
7 * 8 = 56
8 * 7 = 56
14 * 4 = 56
28 * 2 = 56
56 * 1 = 56
The numbers are 56 and 57.
(+7 and +8) and (-7 and-8)
The two numbers with the sum of 15 and the product of 56 are: 7 + 8 = 15 7 x 8 = 56
The numbers are 56 and 57.
86
56 = 7 x 8 = 7 x 23 then 56 is not a product of 3different prime numbers
no
7*8=56
The numbers are 56 and 57.
(+7 and +8) and (-7 and-8)
The two numbers with the sum of 15 and the product of 56 are: 7 + 8 = 15 7 x 8 = 56
14x4
-56 and -1 -56+(-1)=-57 -56*(-1)=56
There is no set of odd numbers whose product is 56 since the latter is even.
No becaues as a product of its prime factors: 2*2*2*7 = 56 or as 23*7 = 56
No because as a product of its prime factors: 2*2*2*7 = 56
The numbers are 56 and 57.