90
Minus 270 degrees which is equivalent to a quarter anti-clockwise turn, or +90 degrees.
270 rule represent a 270 rotation to the left which is very easy
The effect of the rotation is the same as that of a 90 degree clockwise rotation. In matrix notation, it is equivalent to [post-]multiplication by the 2x2 matrix: { 0 1 } {-1 0 }
Both will end up on the same place. Using a compass rose as an example: 270 clockwise will point to the west. 90 counterclockwise will also point west.
It is multiplication by the 2x2 matrix 0 1-1 0
Minus 270 degrees which is equivalent to a quarter anti-clockwise turn, or +90 degrees.
A rotation of 270 degrees clockwise is equivalent to a rotation of 90 degrees counterclockwise. In a Cartesian coordinate system, this means that a point originally at (x, y) will move to (y, -x) after the rotation. Essentially, it shifts the point three-quarters of the way around the origin in the clockwise direction.
270 rule represent a 270 rotation to the left which is very easy
The effect of the rotation is the same as that of a 90 degree clockwise rotation. In matrix notation, it is equivalent to [post-]multiplication by the 2x2 matrix: { 0 1 } {-1 0 }
3 quarters clockwise is 270 degrees clockwise or 90 degrees anti(counter)-clocwise
Move it 3 times* * * * *or once in the anti-clockwise direction.
270
Both will end up on the same place. Using a compass rose as an example: 270 clockwise will point to the west. 90 counterclockwise will also point west.
Three quarters of a turn clockwise is equivalent to a 270-degree rotation in that direction. Starting from a position facing forward, this rotation would turn you to face directly downward. Essentially, it moves you three-quarters of the way around a circle.
All rotations, other than those of 180 degrees should be further qualified as being clockwise or counter-clockwise. This one is not and I am assuming that the direction of rotation is the same as measurement of polar angles. Also, a rotation is not properly defined unless the centre of rotation is specified. I am assuming that the centre of rotation is the origin. Without these two assumptions any point in the plane can be the image. With the assumptions, for which there is no valid reason, the image is (3, -4).
It is the binary function: f(x, y) = (y, -x)
AB --clockwise-------------\ B C ----------------------------/ AC AB --counter-clockwise--\ CA C ----------------------------/ B