"what plus what gives 21" or simply we can say: x + y = 21.
Choose any value of x(say, 2) then we get y = 21-2 =19.
If we put x = 20 then we get y = 1.
We can write a few pairs satisfying the condition as: (1,20), (9,12), (-21,42), (0,21), (2,19),...
There exists infinitely many values of x and y.
However, if we talk about only natural numbers then we can write all the values of x and y. But, if we talk about real numbers then we have infinite values of x and y.
6 + 3 + 21 + 63 + 21 = 114
55 + 34 + 31 + 27 + 21 + 21 + 20 + 17 + 15 + 15 = 256
The answer to 21 plus 16 is 37.
32+14+20+18+16+31+21+16=168
The statement 10 plus 21 equals 31 in total. It can also be written as 10 + 21 = 31.
You can't. 17 + 2n = 21 + 2n gives: 2n = 4 + 2n which gives 0=4 which is not possible so the sum is not solveable.
6 + 3 + 21 + 63 + 21 = 114
21
Adding 79 to 321 gives 400 as the result(79+321).
To find the value of d. SO: if d + 21 = 25, subtract 21 from each side, gives d = 25 - 21, so d = 4
21+21+19+19=80
21+21+17=59
(21-21)+(21-21)+21 = 0+0+21 = 21
what plus what gives me 24
55 + 34 + 31 + 27 + 21 + 21 + 20 + 17 + 15 + 15 = 256
The answer to 21 plus 16 is 37.
To find two-thirds of 21, you multiply 21 by 2/3, which equals 14. Then, adding 166 to 14 gives you 180. Therefore, 166 plus two-thirds of 21 equals 180.