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If the exterior angle of a regular polygon is 108 degrees how many sides does the polygon have?
That's true if the interior angles are 108 degrees, but a regular polygon cannot have exterior angles of 108 degrees.
What is the sum of the measures of the interior angles of a regular polygon if each exerior angle measures 72 degrees?
There are 5 interior angles and each one measures 108 degrees (180-72). Since the sum of exterior angles of any polygon is 360⁰, then that polygon would have 5 angles (360/72). So the sum of interior angle measures is 540⁰.
What is the size of each exterior angle of a regular pentagon?
Interior angles are 108o. 360 - 108 = 252o for each exterior angle * * * * * Each exterior angle is 360/5 = 72 degrees, NOT 252. The 108 for the interior angle is correct, but to get from interior to exterior you subtract from 180, not 360!
How many degrees are on the outside of a pentagon?
The total of the interior angles of a pentagon = 540 (in a regular pentagon, each interior angle is 108 degrees). The exterior angles would then be 5*(360-108) = 5*252 = 1260 degrees.
What is the interior angle of a regular pentagon?
The sum of the interior angles in a pentagon is (5-2)180 degrees or 3x180 degrees=540. Since it is regular each angle has the same measure and so each is 540/5=108 degrees.
