That's true if the interior angles are 108 degrees, but a regular polygon cannot have exterior angles of 108 degrees.
There are 5 interior angles and each one measures 108 degrees (180-72). Since the sum of exterior angles of any polygon is 360⁰, then that polygon would have 5 angles (360/72). So the sum of interior angle measures is 540⁰.
Interior angles are 108o. 360 - 108 = 252o for each exterior angle * * * * * Each exterior angle is 360/5 = 72 degrees, NOT 252. The 108 for the interior angle is correct, but to get from interior to exterior you subtract from 180, not 360!
The total of the interior angles of a pentagon = 540 (in a regular pentagon, each interior angle is 108 degrees). The exterior angles would then be 5*(360-108) = 5*252 = 1260 degrees.
The sum of the interior angles in a pentagon is (5-2)180 degrees or 3x180 degrees=540. Since it is regular each angle has the same measure and so each is 540/5=108 degrees.
A polygon with any number of sides can have an interior angle measuring 108 degrees.
Obtuse
The interior angle of any regular polygon can be calculated using the formula 180 * (n - 2) / n, where n is the number of sides. In this case, since each exterior angle measures 72 degrees, the interior angle would be 180 - 72 = 108 degrees. So the measures of the interior angles in this regular polygon would be 108 degrees.
A [regular] pentagon.
108 degrees
Each exterior angle: 72 degrees Each interior angle: 108 degrees
That's true if the interior angles are 108 degrees, but a regular polygon cannot have exterior angles of 108 degrees.
An exterior angle of 2520 degrees is impossible. Assuming you mean 252 degrees, this would make each interior angle 108 degrees, as 360- 252 = 108. A regular polygon with 108-degree interior angles has 5 sides, or in other words, it is a regular pentagon.
In general, this question cannot be answered. Any polygon can have an interior angle of 108 degrees. For example, a triangle with angles of 108, 32 and 40 degrees; or a quadrilateral with angles of 108, 72, 90 and 90 degrees and so on.In the rare event that the polygon is a regular polygon, then suppose it has n sides.The sum of its interior angles is then (n-2)*180 degreesSo that each interior angle is (n-2)*180/n degrees.Thus (n-2)*180/n = 108(n-2)*180 = 108*n180n - 360 = 108n72n = 360n = 5 sides.
A polygon with interior angle measures of 108 would be a pentagon
If its a regular pentagon then it will have 5 sides
It is a 5 sided regular pentagon and each interior angle measures 108 degrees