A Pentagon has an interior angle of 108 degrees.
That's true if the interior angles are 108 degrees, but a regular polygon cannot have exterior angles of 108 degrees.
There are 5 interior angles and each one measures 108 degrees (180-72). Since the sum of exterior angles of any polygon is 360⁰, then that polygon would have 5 angles (360/72). So the sum of interior angle measures is 540⁰.
Interior angles are 108o. 360 - 108 = 252o for each exterior angle * * * * * Each exterior angle is 360/5 = 72 degrees, NOT 252. The 108 for the interior angle is correct, but to get from interior to exterior you subtract from 180, not 360!
The total of the interior angles of a pentagon = 540 (in a regular pentagon, each interior angle is 108 degrees). The exterior angles would then be 5*(360-108) = 5*252 = 1260 degrees.
The sum of the interior angles in a pentagon is (5-2)180 degrees or 3x180 degrees=540. Since it is regular each angle has the same measure and so each is 540/5=108 degrees.
A polygon with any number of sides can have an interior angle measuring 108 degrees.
Obtuse
The interior angle of any regular polygon can be calculated using the formula 180 * (n - 2) / n, where n is the number of sides. In this case, since each exterior angle measures 72 degrees, the interior angle would be 180 - 72 = 108 degrees. So the measures of the interior angles in this regular polygon would be 108 degrees.
A [regular] pentagon.
108 degrees
That's true if the interior angles are 108 degrees, but a regular polygon cannot have exterior angles of 108 degrees.
Each exterior angle: 72 degrees Each interior angle: 108 degrees
An exterior angle of 2520 degrees is impossible. Assuming you mean 252 degrees, this would make each interior angle 108 degrees, as 360- 252 = 108. A regular polygon with 108-degree interior angles has 5 sides, or in other words, it is a regular pentagon.
In general, this question cannot be answered. Any polygon can have an interior angle of 108 degrees. For example, a triangle with angles of 108, 32 and 40 degrees; or a quadrilateral with angles of 108, 72, 90 and 90 degrees and so on.In the rare event that the polygon is a regular polygon, then suppose it has n sides.The sum of its interior angles is then (n-2)*180 degreesSo that each interior angle is (n-2)*180/n degrees.Thus (n-2)*180/n = 108(n-2)*180 = 108*n180n - 360 = 108n72n = 360n = 5 sides.
To find the number of sides of a regular polygon, you can use the formula: Number of sides = 360 degrees ÷ Measure of each interior angle. In this case, if one interior angle is 108 degrees, the regular polygon has 360 ÷ 108 = 3.33 sides. Since a polygon cannot have a fractional number of sides, we round down to the nearest whole number. Therefore, the regular polygon has 3 sides, which makes it an equilateral triangle.
A polygon with interior angle measures of 108 would be a pentagon
If its a regular pentagon then it will have 5 sides