== 29x blank== 87 ==
-1
-16
2x + 3y = 29x= 4 find x 29x= 4 x = (4/29) sub x into the first part of the sum 2x + 3y = 4 2*(4/29) + 3y = 4 note * means multiply (8/29) + 3y = 4 3y = 4 - (8/29) 3y = (108/29) note 4* 29 minus 8 = 108 y = (36/29) there is probably a quicker way to do this.
If: x = 2/3 and x = 5/7 Then: (3x-2)(7x-5) = 0 Equation: 21x2-29x+10 = 0
(7x-3)(2x+5) 14x2 + 29x - 15, write 29x = 35x - 6x = 14x2 - 6x + 35x - 15 = (14x2 - 6x) + (35x - 15) = 2x(7x - 3) + 5(7x - 3) = (7x-3)(2x+5)
(5x - 1)(x + 6)
14x2 + 29x - 15= 14x2 + 35x - 6x - 15= 7x(2x + 5) - 3(2x + 5)= (2x + 5)(7x - 3)
It is -29x + 3, exactly as in the question.
2x + -94x - 29x-121x
10x2 - 29x = 21 10x2 - 29x - 21 = 0 so x = -0.6 or x = 3.5
(2x+5)(7x-3)=14x2 +29x-15
4x2+29x-24 = (4x-3)(x+8) when factored
I am assuming the question is to factor this problem? 5x2 + 29x - 6 (5x - 1)(x + 6)
== 29x blank== 87 ==
29x
x² + 4x -10 + 8/(6x+5)in other words 6x+5 doesn't quite divide completely into the original polynomial; it leaves a remainder of 8.Another Answer:-Dividend: 6x^3 +29x^2 -40x -42Divisor: 6x +5Quotient: x^2 +4x -10Remainder: 8