Another Answer: 12*0+1 = 1
0+1= 1
2 x 0 x 1 + 1 = 0 + 1 = 1
x2+12x+11=0 (x+11)(x+1)=0 x=-11 or x=-1
...if you did not recognize this to be (x - 1)^2... x^2 - 2x + 1 = 0 or x^2 - x - x + 1 = 0 x(x - 1) - 1(x -1) = 0 (x - 1) (x - 1) = 0 x = 1
If x is designated as "multiply," my answer is 0. If x is a "variable," my answer is 1.
1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 - 1 + 1 + 1 + 1 + 1 + 1 x 0= (1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1) + (1 - 1) + (1 + 1 + 1 + 1) + (1 x 0)= 9 + 0 + 4 + 0= 13It depends on if the entire equation is being multiplied by 0 or just the last plus 1. If it is just the last plus 1 then the answer is 13 like shown above. If the entire problem is being multiplied by 0 then the answer is 0.
2 x 0 x 1 + 1 = 0 + 1 = 1
X + 1 - x - 1 = 0, for all x. Regroup: (x - x) + (1 - 1) = 0 + 0.
x^2 + x = 0 x(x+1) = 0 x = 0 and x = -1
x = 0
x^2 + 1 = 0 x^2 - (-1) = 0 x^2 - i^2 = 0 (x - i)(x + i) = 0 x = i or x = -i
1 ***** 1 is not correct. The correct solution is x = -1 or -6. You can easily find it this way: Factorising, we obtain x2 + 7x + 6 = (x + 1)(x + 6) = 0. The above is true if, and only if, either, x + 1 = 0, or, else, x + 6 = 0; that is, if x = -1 or -6, which is the answer we sought. The rule is that two numbers multiply to give a product of zero, if, and only if, one of the two numbers is zero. To check our answer, let's try substitution into the original equation: Does (-1)2 + 7(-1) + 6 = 0? We see that 1 - 7 + 6 = 0. Does (-6)2 + 7(-6) + 6 = 0? We see that 36 - 42 + 6 = 0. The answer is yes, both times, thus assuring us that we have found the correct answer.
x = -1/2 or -5 2x2 + 11x + 5 = 0 ⇒ (2x + 1)(x + 5) = 0 ⇒ (2x + 1) = 0 → x = -1/2 or (x + 5) = 0 → x = -5
(x + 6)(x + 1) = 0 so x = either -1 or -6
(because zero time 1= 0 plus 1)
x= -1 answer: 0
x2+12x+11=0 (x+11)(x+1)=0 x=-11 or x=-1
x2 + 4x + 3 = 0 (x + 1)(x + 3) = 0 x ∈ {-3, -1}