A shape with four sides has four vertices and a shape with three sides has three vertices, so a shape with four sides has more vertices than a shape with three sides.
There is no such shape.
A pentagon has five sides and five vertices
An hexagon is a polygon that has six sides and six vertices.
A geometric shape with 4 sides and 4 vertices is a 4-sided figure, a quadrilateral.
Pentagon , 5 sided shape with 5 vertices Hendecagon , 12 sides and 12 vertices
A shape with four sides has four vertices and a shape with three sides has three vertices, so a shape with four sides has more vertices than a shape with three sides.
A shape with four sides and three vertices does not exist in Euclidean geometry. In Euclidean geometry, a shape must have the same number of sides as vertices. Therefore, a shape with four sides would have four vertices.
you spelled the word strangely so i am not sure what shape you mean a dodecagon has 12 sides a decagon has ten sides a dodecahedron is, i think, a 3-D shape but i don't recall the number of sides it has ============= A dodecahedron has 12 vertices.
Assuming that each vertex is used to connect exactly two sides, all two-dimensional shapes will have the same number of sides as vertices. So a shape with 4 sides will have 4 vertices and a shape with 3 sides will have 3 vertices. Think of a square (4 sides, 4 vertices) and a triangle (3 sides, 3 vertices).
A cube.
A shape with 7 sides.
a shape with 7 vertices
Since the number of sides and vertices is different, it cannot be a 2-dimensional shape. The only 3-dimensional shape with 4 vertices is a tetrahedron and that does not have 6 sides. Consequently, there is no such shape.
A hexagon has 6 sides and 6 vertices.
A dodecagon is a plane shape and so has only one face. It has 12 sides and 12 vertices.
12 sides, 12 angles, 12 vertices