a= 5 , d= 13-5 = 8 , an= 181 an = a + (n-1) x d 181 = 5 + (n-1) x 8 181 - 5 = (n-1) x 8 176 = (n-1) x 8 176/8 = (n-1) 22 = (n-1) 22+1 = 23 n = 23 Hence, 181 is the 23rd term of the given A.P
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The 38th term
This is an Arithmetic Progression with a first term (a) of 3, and a common difference (d) of 5. The formula for the nth term is a(n) = a + (n - 1)d. Then, 78 = 3 + 5(n - 1) = 3 + 5n - 5 = 5n - 2 Thus, 5n = 78 + 2 = 80 And so, n = 80/5 = 16 The 16th term of this AP is 78.
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4 10 16 22 28 34 40 ....... Each term is increased by 6 or nth term = 6n-2
If the first term, t(1) = a and the common difference is r then t(n) = a + (n-1)*r where n = 1, 2, 3, ...