When n=30, 3n-1 = 89 .
3,6,9,12.....
The nth term of a sequence is the general formula for a sequence. The nth term of this particular sequence would be n+3. This is because each step in the sequence is plus 3 higher than the previous step.
Tn = 1 + 3n
8
123456789 * * * * * The nth term is 3n
When n=30, 3n-1 = 89 .
3,6,9,12.....
The nth term of a sequence is the general formula for a sequence. The nth term of this particular sequence would be n+3. This is because each step in the sequence is plus 3 higher than the previous step.
Tn = 1 + 3n
8
The nth term of the sequence is 3n - 2.
16
The nth term of this sequence is 3n + 4
The question does not contain a sequence but a single large number whose digits are the digits of the sequence, 3n run together. There is only one number, not a sequence, so there is no nth term.
The 'n'th term is [ 4 - 3n ].
The 'n'th term is [ 4 - 3n ].