Any number that you choose can be the next number. It is easy to find a rule based on a polynomial of order 5 such that the first five numbers are as listed in the question followed by the chosen next number. There are also non-polynomial solutions. Short of reading the mind of the person who posed the question, there is no way of determining which of the infinitely many solutions is the "correct" one.
The simplest solution, based on a polynomial of order 4 is
U(n) = (-5*n^4 + 70*n^3 - 343*n^2 + 734*n - 84)/12 for n = 1, 2, 3,, ...
and accordingly, the next number is 51.
Incidentally, the sequence is not the list of prime numbers greater than 30 because one is missing.
61
The next number is 41 because the numbers are increasing by increments of 5
it's 0..
The pattern in the sequence is that each number is obtained by multiplying the previous number by 3 and subtracting 1. 1 x 3 - 1 = 2 2 x 3 - 1 = 5 5 x 3 - 1 = 14 14 x 3 - 1 = 41 41 x 3 - 1 = 122 Therefore, the next number in the sequence would be 122 x 3 - 1 = 365.
24, 65.
61
61
If you meant: 31 37 41 43 47 53 then the next prime number is 59
I think the next few numbers in the sequence are 26, 36, 31, 41, 36 because I notice a pattern; add ten, subtract five, add ten
The next number is 41 because the numbers are increasing by increments of 5
It is impossible to say what sequence comes after the given set of numbers. What I can do is to suggest what number might come next in the given sequence.Using the ruleUn = (7n5 - 129n4 + 891n3 - 2859n2 + 4298n - 1488)/24 for n = 1, 2, 3, ...the next number is 85.
-47, -41, -35, -29, -23, -17, -11, -5, 1, etc.
61 81 101 121 141...you get were im coming from!
45
These are the composites between 31 and 41: 32, 33, 34, 35, 36, 38, 39, 40.
(1) Find the difference of the two previous numbers in the sequence. (2) Add 6 to this difference. (3) Take the number from step 2 and add it to the last number in the sequence to find the next number. For example, to find the next number in the sequence. (1) 112 - 77 = 35 (2) 35 + 6 = 41 (3) 112 + 41 = 153
31 and 41 are prime numbers because they have only two factors