One answer is:
t{n} = (59n⁵ - 885n⁴ + 5015n³ - 13275n² + 15446n - 4800)/120
Which gives:
t1 = (59 - 885 + 5015 - 13275 + 15446 - 4800)/120 = 1560/120 = 13
t2 = (59×32 - 885×16 + 5015×8 - 13275×4 + 15446×2 - 4800)/120 = 840/120 = 7
t3 = (59×243 - 885×81 + 5015×27 - 13275×9 + 15446×3 - 4800)/120 = 120/120 = 1
t4 = (59×1024 - 885×256 + 5015×64 - 13275×16 + 15446×3 - 4800)/120 = -600/120 = -5
t5 = (59×3125 - 885×625 + 5015×125 - 13275×25 + 15446×4 - 4800)/120 = -1320/120 = -11
t6 = (59×7776 - 885×1296 + 5015×216 - 13275×36 + 15446×5 - 4800)/120 = 5040/120 = 42
However, I expect your teacher is wanting the much simpler:
t{n} = 19 - 6n
which also gives t{1..5} = {13, 7, 1, -5, -11} but gives a different t6 = -17
The above formulae are only valid for n = 1, 2, ..., 5 as t6 is different.
2n + 1
It is 4n-13 and so the next number will be 11
The nth term is: 5-6n
The nth term of the sequence is 2n + 1.
Un = 4n - 13.
2n + 1
The given sequence is 1, 6, 13, 22, 33. To find the nth term, we can observe that the differences between consecutive terms are 5, 7, 9, and 11, which indicates that the sequence is quadratic. The nth term can be expressed as ( a_n = n^2 + n ), where ( a_n ) is the nth term of the sequence. Thus, the formula for the nth term is ( a_n = n^2 + n ).
It is 4n-13 and so the next number will be 11
(2n-1)(-1)n
The given sequence is 11, 31, 51, 72 The nth term of this sequence can be expressed as an = 11 + (n - 1) × 20 Therefore, the nth term is 11 + (n - 1) × 20, where n is the position of the term in the sequence.
The nth term is: 5-6n
The nth term of the sequence is 2n + 1.
If you mean -1 3 7 11 15 then the nth term is 4n-5 and so the next term will be 19
It is: nth term = 5-4n and so the next term will be -19
Un = 4n - 13.
The nth term is: 3n+1 and so the next number will be 16
The nth term is 6n+1 and so the next term will be 31