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Q: What is the nth term in 1 3 7 11 15?

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It is: nth term = 5-4n and so the next term will be -19

(2n-1)(-1)n

One of the infinitely many possible rules for the nth term of the sequence is t(n) = 4n - 1

The Nth term for a triangle number is: 0.5n(n+1)

3n(n+1] + 5 is the nth term

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It is: nth term = 5-4n and so the next term will be -19

The nth term is 4n-1 and so the next term will be 19

The nth term for that arithmetic progression is 4n-1. Therefore the next term (the fifth) in the sequence would be (4x5)-1 = 19.

2n + 1

tn = 15 - 4n (n = 1,2,3, ... )

It is: nth term = 29-7n

The given sequence is 11, 31, 51, 72 The nth term of this sequence can be expressed as an = 11 + (n - 1) × 20 Therefore, the nth term is 11 + (n - 1) × 20, where n is the position of the term in the sequence.

(2n-1)(-1)n

The nth term of the sequence is 2n + 1.

It is 4n -1 and so the next term will be 23

1...2....3....43...7...11..157 - 3 = 411 - 7 = 415 - 11 = 4(the start of the nth term is 4n)4 x 1 = 4(but the first term is 3, so...)4 -1 = 3nth term = 4n - 1

35 * * * * * That is the next term. The question, however, is about the nth term. And that is 6*n - 1

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