If you mean -1 3 7 11 15 then the nth term is 4n-5 and so the next term will be 19
It is: nth term = 5-4n and so the next term will be -19
The sequence 12, 13, 14, 15 is an arithmetic sequence where each term increases by 1. The nth term can be expressed as ( a_n = 12 + (n - 1) \times 1 ), which simplifies to ( a_n = 11 + n ). Therefore, the nth term of the sequence is ( a_n = n + 11 ).
(2n-1)(-1)n
The given sequence is 11, 31, 51, 72 The nth term of this sequence can be expressed as an = 11 + (n - 1) × 20 Therefore, the nth term is 11 + (n - 1) × 20, where n is the position of the term in the sequence.
The sequence 7, 9, 11, 13, 15 is an arithmetic sequence where the first term (a) is 7 and the common difference (d) is 2. The nth term can be calculated using the formula: ( a_n = a + (n-1) \cdot d ). Thus, the nth term is given by ( a_n = 7 + (n-1) \cdot 2 ), which simplifies to ( a_n = 2n + 5 ).
It is: nth term = 5-4n and so the next term will be -19
The nth term is 4n-1 and so the next term will be 19
The sequence 12, 13, 14, 15 is an arithmetic sequence where each term increases by 1. The nth term can be expressed as ( a_n = 12 + (n - 1) \times 1 ), which simplifies to ( a_n = 11 + n ). Therefore, the nth term of the sequence is ( a_n = n + 11 ).
The nth term for that arithmetic progression is 4n-1. Therefore the next term (the fifth) in the sequence would be (4x5)-1 = 19.
2n + 1
tn = 15 - 4n (n = 1,2,3, ... )
(2n-1)(-1)n
The given sequence is 11, 31, 51, 72 The nth term of this sequence can be expressed as an = 11 + (n - 1) × 20 Therefore, the nth term is 11 + (n - 1) × 20, where n is the position of the term in the sequence.
It is: nth term = 29-7n
1...2....3....43...7...11..157 - 3 = 411 - 7 = 415 - 11 = 4(the start of the nth term is 4n)4 x 1 = 4(but the first term is 3, so...)4 -1 = 3nth term = 4n - 1
It is 4n -1 and so the next term will be 23
The sequence 7, 9, 11, 13, 15 is an arithmetic sequence where the first term (a) is 7 and the common difference (d) is 2. The nth term can be calculated using the formula: ( a_n = a + (n-1) \cdot d ). Thus, the nth term is given by ( a_n = 7 + (n-1) \cdot 2 ), which simplifies to ( a_n = 2n + 5 ).