You add the 2 numbers before e.g. 2+3=5
0, 1, 1 (0+1), 2 (1+1), 3 (2+1), 5 (2+3), 8 (3+5), 13(5+8), 21 (13+8), 34 (21+13),....and so on.
it is basically a pattern e.g. 1 2 3 4 5 6 7 8 9 10 11 1 2 1 3 1 4 1 5 1 6 3 1 4 1 5 9 2 6 5 3 5 8 9 7 9
1+1=2 1+2=3 2+3=5 3+5=8 5+8=13 8+13=21 13+21=34 and so on. In each case, n=n becomes the next additional calculation.
The answer is (no.) x3 = (no. 2) - 1 = (no. 3) x3= (no.4) x4 and so on... 1 x 3 = 3 - 1 = 2 x 3 = 6 - 1 = 5 x 3 = 15 - 1 = 14 x 3 = 42 - 1 = 41. :D Hope i helped
this series increments in powers of 3 like 1+3^0=2 2+3^1=5 5+3^2=14 14+3^3=41 and so on....
You add the 2 numbers before e.g. 2+3=5
11
0, 1, 1 (0+1), 2 (1+1), 3 (2+1), 5 (2+3), 8 (3+5), 13(5+8), 21 (13+8), 34 (21+13),....and so on.
it is basically a pattern e.g. 1 2 3 4 5 6 7 8 9 10 11 1 2 1 3 1 4 1 5 1 6 3 1 4 1 5 9 2 6 5 3 5 8 9 7 9
Start at 1. Multiply by 3. Subtract 1. Multiply by 3. Subtract 1. Repeat this pattern.
1+1=2 1+2=3 2+3=5 3+5=8 5+8=13 8+13=21 13+21=34 and so on. In each case, n=n becomes the next additional calculation.
2
The answer is (no.) x3 = (no. 2) - 1 = (no. 3) x3= (no.4) x4 and so on... 1 x 3 = 3 - 1 = 2 x 3 = 6 - 1 = 5 x 3 = 15 - 1 = 14 x 3 = 42 - 1 = 41. :D Hope i helped
minus 6, plus 3, minus 6, plus 3...
You start with two integers, usually 0 and 1 or 1 and 1 and get the next number in the pattern by adding the two previous numbers. For example starting with 1 and 1 , 1 + 1 = 2 ,so the sequence is now 1 1 2 1+ 2 = 3 , so the sequence is 1 1 2 3 2+3 = 5 . " " " " 1 1 2 3 5 The formula is an = an-1 + an-2. where a0 and a1 are given and n > 1.
5/(√3 - 1)= 5(√3 + 1)/(√3 - 1)(√3 + 1)= (5√3 + 5)/[(√3)2 - 12)= (5√3 + 5)/(3 - 1)= 5√3 + 5)/2= 5√3/2 + 1/2