Sum of interior angles of a n-gon is 180*(n-2)
So for a 10-gon (decagon), the sum would be 180*8 = 1440 degrees.
That is true whether the polygon is convex or not (as long as its sides do not intersect).
A convex polygon.
180x(N-2)(interior angle) All polygon of the sums of exterior angles is 360. (if convex)
The angles between adjacent sides of a polygon that are interior to the polygon. If the polygon is convex, the interior angles are always less than 180 degrees. If it is concave, at least one interior angle will be greater than 180 degrees.
the sum of the interior angles of a 35-gon.
Use this form to work out the problem: (n - 2)180° where n is the number of sides Suppose that we have a regular polygon. This is the example of a convex polygon. Given that we have a 5-sided convex polygon, we obtain: (5 - 2)180° = 3 * 180° = 540°
No. In a convex polygon the sum of the interior angles is (n-2)*180 deg where n is the number of interior angles. In a non-convex polygon this is not necessarily true.
The sum of the interior angles of any polygon of n sides is equal to 180(n - 2) degrees.
for novanet - 9,540
9540 degrees
33 sides
a convex polygon has 6 sides . What is the sum of the measure of its interior angles?
180(17 - 2) = 2,700 degrees.
360 degrees. The sum of the measures of the exterior angles any convex polygon will always be 360 degrees. The formula for finding the sum of the measures of the interior angles is 180(n-2) when n= the total number of sides the polygon has.
It depends on convex WHAT!
The interior angles of a 14 sided polygon add up to 2160 degrees
A convex polygon.
Yes, the angle sums will be the same regardless of whether or not it is a convex polygon.