What three consecutive integers equals negative sixty three?

Answer 1

Let the consecutive integers be 'n' 'n+1' & 'n+2'

Hence

n + n+1 + n+2 = -63

3n + 3 = -63

3n = -66

n = =66/3

n = -22

Hence

n + 1 = -21

n + 2 = -20

Answer 2

Since you know that the average of the three integers is going to be -63/3 = -21, you know that there must be one integer either side of these. Therefore, -20 + -21 + -22 = -63.