(12 + 14) + (16 + 18) = 60 26 + 34 = 60
Answer: The even numbers are 62, 64, 66, and 68
The numbers are 20, 22, 24 and 26.
There are no such numbers. If S is the sum of any 4 consecutive integers then S = 2 (mod 4) In other words, any four consecutive integers add up to an even number that is NOT dvisible by 4.
Average is 41 so numbers are 39½, 40½, 41½ and 42½If you meant to put consecutive even numbers then 38, 40, 42 and 44
No.Any four consecutive numbers must contain two even numbers and two odd numbers.Adding two odd numbers together always gives an even number.Adding two even numbers always gives an even number.To end up with an odd number you need to add and odd number of odd numbers (3 of them, or 5, 7 etc) together.The nearest ways to get four consecutive numbers to come close to 39 are ...* 8+9+10+11 = 38or * 9+10+11+12 = 42
No. The sum of four consecutive integers is two odd numbers plus two even numbers which is an even number. 2001 is an odd number, therefore it cannot be the sum of four consecutive numbers.
Let the numbers be n, n+1, n+ 2, n+3. Hence n + n+1 + n+ 2 + n+3 = 35 Collect like terms 4n + 6 = 35 Subtract '6' from both sides 4n = 29 Divide both sides by '4' n = 7.25 , 8.25, 9.25, 10.25
Answer: The even numbers are 62, 64, 66, and 68
There is no set of four consecutive numbers (odd or even) whose sum equals 169.
The numbers are 4 and 6.
The numbers are 20, 22, 24 and 26.
The numbers are 82, 84, 86 and 88.
The numbers are 28, 30, 32 and 34.
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If n is the first number, n + n + 1 + n + 2 + n + 3 will be the sum, which is 4n + 6. 4n is always even, and 6 is even. Therefore, the sum of four consecutive numbers is always even.
30
It is 260.