Some do, some don't. A regular polyhedron such as the tetrahedron has none whereas an irregular one like the parallelepiped can have several.
A rectangle is a two-dimensional shape, so it doesn't have faces in the way that three dimensional shapes have. A rectangle has four edges and four corners.
Bases are faces but faces are not necessarily bases.
A cube has 6 faces
2 solid shapes together have 8 faces, 12 edges 8 vertices
Polyhedrons are three-dimensional shapes with flat faces, straight edges, and sharp corners, known as vertices. Examples of polyhedrons include cubes, pyramids, prisms, and dodecahedrons. These shapes have a closed surface and are made up of polygons, which are two-dimensional shapes with straight sides.
There are infinitely many shapes that do.
Spheres
A rhombus is a two dimensional figure while the concept of {faces, vertices and edges} is relevant to 3-dimensional shapes.
No, two dimensional shapes do not have faces
its has parallel faces and edges
Such a shape cannot exist in ordinary 3 dimensional space.
A tetrahedron has no parallel edges. In a tetrahedron, which is a three-dimensional shape with four triangular faces, each pair of edges connects different vertices, ensuring that no two edges run parallel to each other. Thus, all six edges of a tetrahedron are distinct and not parallel.
Any convex three dimensional figure with straight edges (or plain faces) will have polygons for bases so there is an infinity of such shapes.
It has 9 faces It has 21 edges Its end faces are parallel to each other
It is the set of points, in 3-dimensional space, defined by the intersection of two planes which define faces of the shape.
This question is faulty. Only 2-dimensional shapes can have their sides counted. For a 3-dimensional shape, you must count either edges or faces.
circle, sphere and another shape do not have faces or edges