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How many square tiles of side 9 cm are required to cover a rectangle of length 36 cm and breadth 18 cm exactly without any tiles overlapping?
8 of them.
How many 9 inch square tiles would be required to cover the entire floor?
One 9 inch square tile would presumably be 9in x 9in or 81in2, unless you are meaning 3in x 3in tile which is then 9in2. Regardless, the answer to your question is the total area of the floor (in square inches) divided by the total area of one tile (in square inches).
How many 18inx18inch tiles are needed to cover 121 sq ft?
An 18 inch by 18 inch tile is one and a half feet by one and a half feet, or 3/2 ft by 3/2 feet. Its area is two and a quarter square feet. (3/2 x 3/2 = 9/4). The number of tiles needed is 121 divided two and a quarter. That's 121 divided by 9/4 = 121 x 4/9 = 54 (rounding up to a whole number of tiles. But this is the minimum number of tiles needed. The real answer will depend on the shape of the area to be covered, which determines how many tiles will need to be cut and how much wastage there will be.
How many 4 inch tiles in 1 square foot?
One square foot is 12 inches by 12 inches so you can fit in it 9 tiles in a 3 tiles by 3 tiles square.
How many square yards of carpeting is needed to cover a floor area of 1600 square feet?
9 square feet = 1 square yard 1,600 square feet = 1777/9 square yards
