8 of them.
One 9 inch square tile would presumably be 9in x 9in or 81in2, unless you are meaning 3in x 3in tile which is then 9in2. Regardless, the answer to your question is the total area of the floor (in square inches) divided by the total area of one tile (in square inches).
An 18 inch by 18 inch tile is one and a half feet by one and a half feet, or 3/2 ft by 3/2 feet. Its area is two and a quarter square feet. (3/2 x 3/2 = 9/4). The number of tiles needed is 121 divided two and a quarter. That's 121 divided by 9/4 = 121 x 4/9 = 54 (rounding up to a whole number of tiles. But this is the minimum number of tiles needed. The real answer will depend on the shape of the area to be covered, which determines how many tiles will need to be cut and how much wastage there will be.
One square foot is 12 inches by 12 inches so you can fit in it 9 tiles in a 3 tiles by 3 tiles square.
9 square feet = 1 square yard 1,600 square feet = 1777/9 square yards
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6' x 9' (54 square feet) = 6 square yards of tiles needed.
Answer:320 tilesMath:floor is 144 inches X 180 inches144 / 9 = 16180 / 9 = 2020 X 16 = 320 tiles
2880 exactly, but if this is ceramic tiles you have to account for grout lines. extras would be recommended
There are 3 tiles per foot, so 9 per square foot. 3 ft x 5 ft = 15 sq ft x 9 tiles per sq ft = 135 tiles
Get your sq. footage by multiplying length times width, then find out how many tiles it takes to measure to a foot length. In this case 4 tiles = 3'. and 3 x 3 is 9 so divide 9 into your sq. footage and then you have your answer.
nowhere.
1242
There is 144 sq inches in a sq foot so 12 x 15 = 180 sq ft x 144 = 25920 / 81 (9 x 9) = 320 tiles. Be sure to buy extra for waste and mistakes...
It depends on how big the tiles are.