An 18 inch by 18 inch tile is one and a half feet by one and a half feet, or 3/2 ft by 3/2 feet.
Its area is two and a quarter square feet. (3/2 x 3/2 = 9/4).
The number of tiles needed is 121 divided two and a quarter.
That's 121 divided by 9/4 = 121 x 4/9 = 54 (rounding up to a whole number of tiles.
But this is the minimum number of tiles needed. The real answer will depend on the shape of the area to be covered, which determines how many tiles will need to be cut and how much wastage there will be.
Assuming it's a 4x4 wall, 64 tiles
5*6=30*12=360/4=90 tiles
You would need a total of 89 tiles (88.88 tiles exactly) with those measurements to cover that area.
Lets do length and width in terms of tiles. The length is 6m/0.2m/tile 30 tiles and the width is 5m/0.2m/tile 25 tiles. Then the area is l X w 30 tiles X 25 tiles 750 square tiles. Since each tile is square, 750 tiles.
that question depends on how big your tiles are and how big your floor is
The amount of tiles needed to cover a floor will depend on the size of the floor.
49 tiles
157 18 by 18 tiles are needed to cover 352 square feet.
It depends on how big the tiles are.
25 geinus
128.2 tiles
226 tiles
i cant give you an answer with out know how big the tiles are sorry :(
The answer will depend on the size of the tiles.
1540
616 3x6 inch tiles are needed to cover exactly 77 square feet.
2400 tiles if you don't get any extra