7 times 11
Let the numbers equal x and y.... So you have the two equations x+y=77 and 6x=y Using substitution.... x+6x=77 7x=77 x=11 Plugging x back into our original equation.... 11+y=77 y=66 So your two numbers are 11 and 66
11 times 7
77*34=2,618
11 times 7
Nothing can fall "between 77". 77 is one number; you need an interval for any numbers to fall BETWEEN.
Let the numbers equal x and y.... So you have the two equations x+y=77 and 6x=y Using substitution.... x+6x=77 7x=77 x=11 Plugging x back into our original equation.... 11+y=77 y=66 So your two numbers are 11 and 66
11 times 7
77 x 5 = 385
77 multiplied by 8 is 616.
77x2= 154 77+77=154
77*34=2,618
1 x 77, 7 x 11
231 is equal to 77 times 3. So the prime factors of 231 are 3, 7 and 11.
(-77,3)(-33,7)(-21,11)(77,-3)(33,-7)(21,-11)
To find two numbers that multiply to equal 5005, you can factor 5005. The prime factorization of 5005 is 5 x 7 x 11 x 13. Therefore, several pairs of numbers can be multiplied to yield 5005, such as 65 and 77 (since 65 x 77 = 5005).
11 x 7 = 77
1*77,11*7