Let the numbers equal x and y.... So you have the two equations x+y=77 and 6x=y Using substitution.... x+6x=77 7x=77 x=11 Plugging x back into our original equation.... 11+y=77 y=66 So your two numbers are 11 and 66
54
45
57
= The sum of two numbers is -42 the first number minus the second number is 52 Find the numbers? =
a=58.4615 b=5.2308 c=41.3076
54
45
57
= The sum of two numbers is -42 the first number minus the second number is 52 Find the numbers? =
a=58.4615 b=5.2308 c=41.3076
Take two numbers. Throw (the first number) into a box (the second number) times. The total amount in the box is then the product of the two numbers.
To find the second common multiple of two numbers, you first need to identify the least common multiple (LCM) of the two numbers. The LCM is the smallest number that is a multiple of both numbers. Once you have the LCM, you can then find the second common multiple by adding the LCM to the LCM itself. This will give you the second common multiple of the two numbers.
four times a number is 6 more than three times a second number while 8 times the first number is 22 less than 7 times the second number. find the 2 numbers
y = 3x+8 x + y = 72 x = 16 y = 56
The numbers are 14, 16 and 18.
25 and 14
This problem asks us to find 2 numbers, n1 and n2, with the following relations between them: * n2 = 4 n1 * n1 + n2 = 45 Substituting the first equation into the second one gives us: * n1 + 4n1 = 45 which gives us * n1 = 9. We can now use this solution to find n2 with the first equation * n2 = 4 n1 = 36 So the first number is 4, the second number is 36.