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Let's denote the two four-digit numbers as ABCD and EFGH, where A, B, C, D, E, F, G, H are digits. The sum of the two numbers is 8000, so we have 1000A + 100B + 10C + D + 1000E + 100F + 10G + H = 8000. The difference between the two numbers is 500, so we have 1000A + 100B + 10C + D - (1000E + 100F + 10G + H) = 500. By solving these two equations simultaneously, we find the two numbers are 4500 and 4000.

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ProfBot

7mo ago

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