323 and 177
501
To find the average of a set of numbers, you add all the numbers together and then divide by the total number of values. In this case, the sum of 124, 148, 207, and 21 is 500. Since there are 4 numbers in the set, you divide 500 by 4 to get an average of 125.
Let's denote the two four-digit numbers as ABCD and EFGH, where A, B, C, D, E, F, G, H are digits. The sum of the two numbers is 8000, so we have 1000A + 100B + 10C + D + 1000E + 100F + 10G + H = 8000. The difference between the two numbers is 500, so we have 1000A + 100B + 10C + D - (1000E + 100F + 10G + H) = 500. By solving these two equations simultaneously, we find the two numbers are 4500 and 4000.
The sum of the first 500 counting numbers (1-500) is 125,001.
501
177 and 323.
The 2 numbers that total 500 and are different by 156 are 328 and 172.
Answer : In total there are 22 numbers.
Let the two numbers be ( x ) and ( y ). According to the problem, we have the equations ( x + y = 500 ) and ( x - y = 156 ). Solving these simultaneously, we can add the two equations to get ( 2x = 656 ), which gives ( x = 328 ). Substituting back, we find ( y = 500 - 328 = 172 ). Thus, the two numbers are 328 and 172.
503 and 521.
500
146% equals:146/10073/501 23/50
501
Let's denote the two numbers as x and y. We can set up a system of equations to represent the given information: x + y = 500 and x - y = 156. By solving this system simultaneously, we can find the values of x and y. Adding the two equations eliminates y, giving us 2x = 656, so x = 328. Substituting x back into the first equation gives us y = 500 - 328 = 172. Therefore, the two numbers are 328 and 172.
500 and 490 are both whole numbers. They are consecutive integers, with 500 being 10 greater than 490. In terms of mathematical operations, their sum is 990, and their difference is 10. These numbers can also represent quantities in various contexts, such as measurements or scores.
To find the average of a set of numbers, you add all the numbers together and then divide by the total number of values. In this case, the sum of 124, 148, 207, and 21 is 500. Since there are 4 numbers in the set, you divide 500 by 4 to get an average of 125.
0.146 = 146/1000 or 73/500 in fraction