ANSWER: The two numbers required are not whole numbers. These are 43.135 and 20.865.
Solution 1:
Assuming you want whole numbers:
Prime factorization for 900 is
2 x 2 x 3 x 3 x 5 x 5
You cannot combine these in any way to have a sum that is 64. You can with 65, but not 64.
Solution 2:
Let:
x = first number
y = second number
x * y = 900 (Equation 1)
x + y = 64
x = 64 - y (Equation 2)
Substitute Eq. (2) in Eq. (1):
x * y = 900
(64 - y) y = 900
64y - y2 = 900
- y2 +64y - 900 = 0 (Equation 3)
multiply Eq. (3) by -1
y2 - 64y + 900 = 0
using quadratic equation:
y1 = 43.135 y2 = 20.865
Therefore, the two numbers are 43.135 and 20.865
How about: 30 and 30
If the sum of 2 numbers is 25 and their product is 156, the numbers are 12 and 13.
1+30=31 and 1x30=30
It's unclear whether you want two numbers that add to a sum or multiply to a product. 25 x 4 = 100 25 + 75 = 100
There are an infinite number of groups of numbers whose sum, difference, product, quotient etc. is equal to 40 . But there are not four numbers that equal 40. In fact, there is only one number that equals 40. The number is . . . . . 40 .
900
The answer is ..............180 and 5. So 180 + 5 = 185 and 180*5=900.
How about: 30 and 30
29 & 41
The two numbers are 180 and 5 180 + 5 = 185 180 x 5 = 900
1 2 3
900 - 30 times 30
No - the product of numbers is the answer to a multiplication sum, while the sum of numbers is the answer to an addition sum.
Because summing and taking the product are two entirely different binary operations.
3.268 and 6.372 (approx)
The sum of the first 900 consecutive odd numbers is 810,000.
901