9 and 5
There are 8 numbers between the two given.
59
76 - 14 = 62; 62/2 = 31; 31 + 14 = 45 which is 76 - 31.
24 + 21 = 45 24 - 21 = 3 Therefore, the two numbers are 21 and 24.
9 and 5
5&9
They are 9 and 5
There are 8 numbers between the two given.
They are: 14+15+16 = 45
59
The factors of 14 are: 1, 2, 7, 14 The factors of 45 are: 1, 3, 5, 9, 15, 45 Other than 1, there are no common factors of the two numbers.
76 - 14 = 62; 62/2 = 31; 31 + 14 = 45 which is 76 - 31.
1 goes into 45
Call the unknown numbers s and l for smaller and larger respectively. From the problem statement, l - s = 14 and 4s - 3l = 45. Transpose the first equation to result in l = 14 + s and substitute this into the second equation to result in 4s - 3(14 + s) =45, or 4s - 42 - 3s = 45. or s = 45 + 42 = 87. l is then 101.
59
14 + 15 + 16 = 45