59
76 - 14 = 62; 62/2 = 31; 31 + 14 = 45 which is 76 - 31.
Let's denote the two numbers as x and y. We know that xy = 45 and x + y = 14. To find the two numbers, we can set up a system of equations. From the first equation, we can express y in terms of x as y = 45/x. Substituting this into the second equation gives us x + 45/x = 14. Multiplying through by x gives us x^2 - 14x + 45 = 0. Factoring this quadratic equation gives us (x - 9)(x - 5) = 0. Therefore, the two numbers are x = 9 and y = 5.
24 + 21 = 45 24 - 21 = 3 Therefore, the two numbers are 21 and 24.
Numbers are either prime or they aren't. In this case, 45 is divisible by 3 and 15; sixty-four goes into 2, 4, 8 and 32. The term "relatively prime" compares two numbers and their common factors. If the GCF of the two numbers is 1, then they are "relatively prime."
5&9
They are 9 and 5
They are: 14+15+16 = 45
59
The factors of 14 are: 1, 2, 7, 14 The factors of 45 are: 1, 3, 5, 9, 15, 45 Other than 1, there are no common factors of the two numbers.
76 - 14 = 62; 62/2 = 31; 31 + 14 = 45 which is 76 - 31.
1 goes into 45
Call the unknown numbers s and l for smaller and larger respectively. From the problem statement, l - s = 14 and 4s - 3l = 45. Transpose the first equation to result in l = 14 + s and substitute this into the second equation to result in 4s - 3(14 + s) =45, or 4s - 42 - 3s = 45. or s = 45 + 42 = 87. l is then 101.
Let's denote the two numbers as x and y. We know that xy = 45 and x + y = 14. To find the two numbers, we can set up a system of equations. From the first equation, we can express y in terms of x as y = 45/x. Substituting this into the second equation gives us x + 45/x = 14. Multiplying through by x gives us x^2 - 14x + 45 = 0. Factoring this quadratic equation gives us (x - 9)(x - 5) = 0. Therefore, the two numbers are x = 9 and y = 5.
59
14 + 15 + 16 = 45
Maximum = 45 Minimum = 14 Range = Max - min = 45 - 14 = 31