9 and 5
59
76 - 14 = 62; 62/2 = 31; 31 + 14 = 45 which is 76 - 31.
Let's denote the two numbers as x and y. We know that xy = 45 and x + y = 14. To find the two numbers, we can set up a system of equations. From the first equation, we can express y in terms of x as y = 45/x. Substituting this into the second equation gives us x + 45/x = 14. Multiplying through by x gives us x^2 - 14x + 45 = 0. Factoring this quadratic equation gives us (x - 9)(x - 5) = 0. Therefore, the two numbers are x = 9 and y = 5.
24 + 21 = 45 24 - 21 = 3 Therefore, the two numbers are 21 and 24.
Numbers are either prime or they aren't. In this case, 45 is divisible by 3 and 15; sixty-four goes into 2, 4, 8 and 32. The term "relatively prime" compares two numbers and their common factors. If the GCF of the two numbers is 1, then they are "relatively prime."
The two numbers that multiply to 45 and add up to -14 are -9 and -5. This is because (-9) × (-5) = 45, and (-9) + (-5) = -14.
5&9
They are 9 and 5
They are: 14+15+16 = 45
59
The factors of 14 are: 1, 2, 7, 14 The factors of 45 are: 1, 3, 5, 9, 15, 45 Other than 1, there are no common factors of the two numbers.
76 - 14 = 62; 62/2 = 31; 31 + 14 = 45 which is 76 - 31.
1 goes into 45
Let's denote the two numbers as x and y. We know that xy = 45 and x + y = 14. To find the two numbers, we can set up a system of equations. From the first equation, we can express y in terms of x as y = 45/x. Substituting this into the second equation gives us x + 45/x = 14. Multiplying through by x gives us x^2 - 14x + 45 = 0. Factoring this quadratic equation gives us (x - 9)(x - 5) = 0. Therefore, the two numbers are x = 9 and y = 5.
Call the unknown numbers s and l for smaller and larger respectively. From the problem statement, l - s = 14 and 4s - 3l = 45. Transpose the first equation to result in l = 14 + s and substitute this into the second equation to result in 4s - 3(14 + s) =45, or 4s - 42 - 3s = 45. or s = 45 + 42 = 87. l is then 101.
59
14 + 15 + 16 = 45