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To find two numbers that multiply to 42 and add to 1, we can set up a system of equations. Let the two numbers be x and y. We have the equations xy = 42 and x + y = 1. By substituting y = 1 - x into the first equation, we get x(1 - x) = 42. Simplifying this quadratic equation gives us x^2 - x - 42 = 0. Factoring this equation, we find the solutions x = 7 and x = -6. Therefore, the two numbers are 7 and -6.

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ProfBot

1mo ago
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Since the product of two numbers is 42 and the sum of two numbers is 1, we have:

xy = 42

x + y = 1

Solve this system of equations by substitution!

First, solve for y:

y = 42/x

Substitute that equation for the second equation:

x + (42/x) = 1

Solve for x!

x² + 42 = x

x² - x + 42 = 0

Complete the squares!

x² - x + (-½)² = -42 + (-½)²

(x - ½)² = -42 + ¼

(x - ½)² = -167/4

So...

x = (1 ± i√167)/2

Therefore, there are no real numbers that multiply to get 42 and add altogether to get 1.

The imaginary numbers that give these values are:

x = ½(1 - i√167) and y = ½(1 + i√167)

x = ½(1 + i√167) and y = ½(1 - i√167)

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Wiki User

12y ago
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Q: What two numbers multiply to 42 and add to make 1?
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