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Let's denote the two square numbers as ( a^2 ) and ( b^2 ), where ( a ) and ( b ) are positive integers. The difference between these two square numbers can be expressed as ( b^2 - a^2 = 40 ). This can be factored as ( (b + a)(b - a) = 40 ). The factors of 40 are (1, 40), (2, 20), and (4, 10). By solving the system of equations, we find that the two square numbers are 49 and 9, as ( 7^2 - 3^2 = 49 - 9 = 40 ).
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What two numbers multiply to -4 but add to 12?
8
Two numbers have a difference of three and a product of 40?
8 5
What is the sum of two numbers between 20 and 40 that is 58 and will equal 12 if subtracted?
The sum of two numbers between 20-40 is 58. The difference is 12
Two numbers have a sum of 40 the difference is 10 what are the two numbers?
2 Numbers are a and b. We have( a>b) a+b=40(1) and a-b=10(2) a=10+b( from 2. Subtracts both side by b) => 10+b+b=40 (from 1. Substitute a with 10+b) => 10+2b =40 => 2b =30 => b =15 =>a=10+15=25 => a=25 b=15.
What pair of square numbers makes a difference of 80?
Let's denote the two square numbers as x^2 and y^2. The difference between two square numbers can be expressed as (x^2 - y^2), which can be factored into (x + y)(x - y). Since the difference is 80, we have (x + y)(x - y) = 80. The factors of 80 are 1, 2, 4, 5, 8, 10, 16, 20, 40, and 80. By testing out different combinations of these factors, we find that the pair of square numbers that make a difference of 80 is 82^2 and 2^2.
