Well, honey, the square numbers that have a difference of 40 are 64 and 24. You take the square root of both numbers, subtract them, and boom, there's your answer. Math can be a piece of cake if you just use that noggin of yours.
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The sum of two numbers between 20-40 is 58. The difference is 12
Let's denote the two square numbers as x^2 and y^2. The difference between two square numbers can be expressed as (x^2 - y^2), which can be factored into (x + y)(x - y). Since the difference is 80, we have (x + y)(x - y) = 80. The factors of 80 are 1, 2, 4, 5, 8, 10, 16, 20, 40, and 80. By testing out different combinations of these factors, we find that the pair of square numbers that make a difference of 80 is 82^2 and 2^2.
2 Numbers are a and b. We have( a>b) a+b=40(1) and a-b=10(2) a=10+b( from 2. Subtracts both side by b) => 10+b+b=40 (from 1. Substitute a with 10+b) => 10+2b =40 => 2b =30 => b =15 =>a=10+15=25 => a=25 b=15.
What two numbers have a difference of three a d a product of 40
The numbers are 25 and 15
The numbers are 25 and 15
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3 and 7.
One option is 110 and 70.
40
20
24 + 16 = 40
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15 and 25
The numbers will be the square root of 1120