I believe that a mile was a standard distance in the 1930s. So every mile was exactly as long as every other mile.
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The car was driven 1780 miles. If a car was rented for 2 days, there would be a flat rate of $42 ($21 per day * 2 days = $42). That leaves $178 from the total bill ($220 total - $42 = $178). Take the $178 divided by $0.10 per mile and that leaves you with 1780 miles ($178 / $0.10 per mile = 1780 miles).
That would depend upon the size of the tire. My car has tires that are about 221/4" in diameter which means they have circumference: circumference = π x diameter ≈69.9" which is the distance travelled in one complete revolution of the tire. 1 mile = 63360 in ⇒ revolutions = 1 mile ÷ circumference_of_tire ≈ 63360 in ÷ 69.9 in ≈ 906.43 revolutions per mile My bicycle has tires that are about 271/2" in diameter meaning the number of revolutions is: revolutions ≈ 63360 in ÷ (π x 271/2 in) ≈ 733.39 revolutions per mile
It is 1 cent per mile cheaper.
1 mile is 5280 feet. So, 40 miles per hour is the same as 211,200 feet per hour.
aceeleration = (initial + final) divide by time so a= (0 + 60) divide by 9 a = 6.666666667 mile 18 feet = 0.00340909091 mile s=ut + 0.5at2 s=displacement, u=initial speed, a=acceleration t=time 0.00340909091 mile = 0t +0.5(6.666666667)t2 t2 = 0.00340909091/0.5(6.666666667) t2 =0.0454545455 t = 0.213200716 v=u+at v=final speed v= 0 + 6.666666667(0.213200716) v=1.42133811 so after moving 18ft the speed of the car = 1.42m/s2