Perimeter = length + width + length + width = 2 x (length + width) Given: perimeter = 22in length = width + 3in Thus 22 = 2 x (width + 3 + width) 11 = 2 x width + 3 8 = 2 x width 4 = width So the width is 4in.
It is 22 in by 27 in. ------------------------------------------- How it is solved: The rectangle is 5 in longer than its width, so the dimensions can be given in terms of its width: Its dimensions are width by (width+5) In removing 1 inch squares from the corners, he flaps are going to be (width-2) and (width+5-2) = (width-3) long. Thus the box formed will have volume: volume = (width - 2) in × (width + 3) in × 1 in → volume = width² + width - 6 in³ But we are told this is 500 in³; thus: width² + width - 6 in³ = 500 in³ → width ² + width - 506 = 0 → (width + 23)(width - 22) = 0 → width = -23 or 22 As a length cannot be negative, the width must be 22 in which means the original rectangle is 22 in by 22+5 in = 27 in
Area = Length * Width 24 = 6 * Width so width = 4m
The area of rectangle is : 7820.0
What do we know about the perimeter of a rectangle? perimeter = 2 × (length + width) → 2 × (length + width) = 20 in → length + width = 10 in → length = 10 in - width What do we know about the area of a rectangle: area = length × width → length × width = 24.4524 in² But from the perimeter we know the length in terms of the width and can substitute it in: → (10 in - width) × width = 24.4524 in² → 10 in × width - width² = 24.4524 in² → width² - 10 in × width + 24.4524 in² = 0 This is a quadratic which can be solved by using the formula: ax² + bx + c → x = (-b ±√(b² - 4ac)) / (2a) → width = (-10 ±√(10² - 4 × 1 × 24.4524)) / (2 × 1) in → width = -5 ± ½√(100 - 97.8096) in → width = -5 ±½√2.1904 in → width = -5 ± 0.74 in → width = 4.26 in or 5.74 in → length = 10 in - 4.26 in = 5.74 in or 10 in - 5.74 in = 4.26 in (respectively) By convention the width is the shorter length (though it doesn't have to be) making the width 4.26 in and the length 5.74 in. Thus the rectangle is 5.74 in by 4.26 in
american falls
The width of Victoria Falls is 1708 metres.
Horseshoe Falls is 2,198.16-feet wide. Two-thirds of Horseshoe Falls is?æ located in Canada, while the remaining one-third is located in the United States, in the state of New York. It is part of Niagara Falls.
the width of angel falls is acutally 7 feet
There is no recorded width for Angel Falls. It is a "plunge" waterfall with such a long drop that no width can accurately be measured.
The American Falls is the name of the falls.==============================There are actually three falls at Niagara Falls, two of which are on the American side. The second, and much smaller American falls is called the Bridal Veil Falls. The Bridal Veil Falls is between the American Falls and the Horseshoe Falls, closer to the American Falls.
the length is 600000.95 thank you for asking
The tallest section of falls, called Horseshoe Falls, is a semi-circle approximately 790 meters (2600 ft) feet in width. The smaller American Falls are about 320 meters (1060 ft) and the adjacent stream of Bridal Veil Falls is only about 17 meters (56 ft) wide.
The address of the American Falls District is: 308 Roosevelt St, American Falls, 83211 1219
In height and width, Victoria Falls is rivalled only by South America's Iguazu Falls.
The width is 5604 feet
5604 feet