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The area of rectangle is : 7820.0

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Joanie Koelpin

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2y ago
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9y ago

10mm = 1 cm → 460mm = 460 ÷ 10 cm = 46 cm

Perimeter = 2 x (length + width)

→ length + width = perimeter ÷ 2 = 46 cm ÷ 2 = 23 cm

→ length = 23 cm - width

area = length x width

→ area = (23 - width) x width = 23 x width - width^2 [1]

Using Pythagoras:

length^2 + width^2 = diagonal^2

→ length^2 + width^2 = 17^2

→ (23 - width)^2 + width^2 = 17^2

→ 23^2 - 46 x width + width^2 +width^2 = 17^2

→ 2 x width^2 - 46 x width + 529 - 289 = 0

→ 2 x width^2 - 46 x width + 240 = 0

→ width^2 - 23 x width + 120 = 0

→ 120 = 23 x width - width^2 = area (from [1] above])

→ area = 120 cm^2

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Q: What is the area of a rectangle whose diagonal is 17 cm with a perimeter of 460 mm explaining work with answer?
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