The area of rectangle is : 7820.0
10mm = 1 cm → 460mm = 460 ÷ 10 cm = 46 cm
Perimeter = 2 x (length + width)
→ length + width = perimeter ÷ 2 = 46 cm ÷ 2 = 23 cm
→ length = 23 cm - width
area = length x width
→ area = (23 - width) x width = 23 x width - width^2 [1]
Using Pythagoras:
length^2 + width^2 = diagonal^2
→ length^2 + width^2 = 17^2
→ (23 - width)^2 + width^2 = 17^2
→ 23^2 - 46 x width + width^2 +width^2 = 17^2
→ 2 x width^2 - 46 x width + 529 - 289 = 0
→ 2 x width^2 - 46 x width + 240 = 0
→ width^2 - 23 x width + 120 = 0
→ 120 = 23 x width - width^2 = area (from [1] above])
→ area = 120 cm^2
Perimeter = 5+5+3.5+3.5 = 17 feet
Using Pythagoras: side_length² + side_length² = diagonal² → 2 × side_length² = (3√2)² → 2 × side_length² = 3³ × 2 → side_length² = 3² → side_length = 3 → perimeter = 4 × side_length = 4 × 3 = 12 units.
This has several values.The perimeter is twice the sum of any two numbers whose product is 54.
Perimeter is a unit of length. Area is a unit of area. The two units are not directly convertible.However, the area of a rectangle is length times width, and the perimeter is two times length plus two times width. Given constant perimeter, a square has maximum area, while a very thin rectangle has nearly zero area. (In calculus terms, the limit of the area as length or width goes to zero is zero.)Depending on how you want to name your units, you can always find a rectangle whose perimeter is "larger" than area, but this is a numerical trick that is not valid in any school of thought of mathematics that I know.
If the width is 9' and the length is twice that, the length is 18'; the perimeter is twice the length plus twice the width, which is 36' + 18' = 54 feet.
The perimeter of this square is 45.25 cm
The perimeter of a rectangle whose length is 5cm wit a width of 6cm is 22cm
123
You forgot to put in the length of the rectangle's perimeter.
56 cm Perimeter of a rectangle is given by 2(length + breadth). So, perimeter of given rectangle = 2(18 + 10) = 56
Using Pythagoras' theorem the length of the diagonal is 20 feet
Perimeter = 5+5+3.5+3.5 = 17 feet
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360
That depends on the rectangle! You can have different rectangles with the same area, but with different perimeters.
5x2 + 3x2 = 16