First 9 pages = 9 digit.
That leaves 142 digits.
@ 2 digit per page, that is 142/2 = 71 pages with 2-digit numbers.
So, 9 pages with 1-digit numbers + 71 pages with 2-digit numbers = 80 pages.
315
642
I'm going to go with 172. pages 1-9 = 9 digits pages 10-99 = 180 digiits leaves 219 digits each page from 100 on = 3 digits 219 /3 = 73 99 pages plus 73 page = 172
453 0-9 9 digits 10-99 180 digits 100-250 453 digits
Three digits.
There are exactly 320 pages in 852 digits.
315
1140
642
numbersdigitstotal digits1to991910to99902180100to2251263378Total567
299 pages.
That's going to depend on the subject matter of the book. Besides the digits used to number the pages, an arithmetic book will have a lot more digits in it than, for example, a novel or a book of poetry has.
I'm going to go with 172. pages 1-9 = 9 digits pages 10-99 = 180 digiits leaves 219 digits each page from 100 on = 3 digits 219 /3 = 73 99 pages plus 73 page = 172
There are 9 pages that use a single digit (pages 1-9), leaving 495 digits - 9 pages × 1 digit/page = 486 digits There are 90 pages that use 2 digits (pages 10-99), leaving 486 digits - 90 pages × 2 digits/page = 306 digits There are 900 pages that use 3 digits (pages 100-999); this would be 2,700 digits, so the number of pages is somewhere in the hundreds. 306 digits ÷ 3 digits/page = 102 pages in the hundreds. → total number of pages = 102 + 90 + 9 = 201 pages.
453 0-9 9 digits 10-99 180 digits 100-250 453 digits
Three digits.
381 digits.