First 9 pages = 9 digit.
That leaves 142 digits.
@ 2 digit per page, that is 142/2 = 71 pages with 2-digit numbers.
So, 9 pages with 1-digit numbers + 71 pages with 2-digit numbers = 80 pages.
315
642
I'm going to go with 172. pages 1-9 = 9 digits pages 10-99 = 180 digiits leaves 219 digits each page from 100 on = 3 digits 219 /3 = 73 99 pages plus 73 page = 172
453 0-9 9 digits 10-99 180 digits 100-250 453 digits
Three digits.
There are exactly 320 pages in 852 digits.
315
1140
642
299 pages.
numbersdigitstotal digits1to991910to99902180100to2251263378Total567
I'm going to go with 172. pages 1-9 = 9 digits pages 10-99 = 180 digiits leaves 219 digits each page from 100 on = 3 digits 219 /3 = 73 99 pages plus 73 page = 172
That's going to depend on the subject matter of the book. Besides the digits used to number the pages, an arithmetic book will have a lot more digits in it than, for example, a novel or a book of poetry has.
There are 9 pages that use a single digit (pages 1-9), leaving 495 digits - 9 pages × 1 digit/page = 486 digits There are 90 pages that use 2 digits (pages 10-99), leaving 486 digits - 90 pages × 2 digits/page = 306 digits There are 900 pages that use 3 digits (pages 100-999); this would be 2,700 digits, so the number of pages is somewhere in the hundreds. 306 digits ÷ 3 digits/page = 102 pages in the hundreds. → total number of pages = 102 + 90 + 9 = 201 pages.
453 0-9 9 digits 10-99 180 digits 100-250 453 digits
381 digits.
Three digits.