-1
(48a3+32a2+16a)/4a = 12a2+8a+4
2a3 - 128 = 2*(a3 - 64) = 2*(a -4)*(a2 + 4a + 16)
4a+3b can not be algebraically simplified. It can be evaluated if you assign values to a and b.
(4a)2 or 16a2
4a+2b+a
a3-4a = a(a2-4) when factored
4a3 - 4a2 = 4a2*(a - 1)
20a + 45 = 5(4a + 9)
It is: (a+1)(a+3) when factored
Assuming the missing signs are pluses, that factors to (4a + 3)(a + 3)
48a3 + 32a2 + 4a = 4a(12a2 + 8a + 1)
idont know
To divide ( 48a^3 + 32a^2 + 16a ) by ( 4a ), you can divide each term individually. This gives: ( \frac{48a^3}{4a} = 12a^2 ) ( \frac{32a^2}{4a} = 8a ) ( \frac{16a}{4a} = 4 ) Thus, the result is ( 12a^2 + 8a + 4 ).
You have to multiply base x height - in this case, you obtain (4a)(2a+b). This can't be simplified; you can leave it as it is (factored), or multiply it out to obtain 8a2 + 4ab.
(48a3+32a2+16a)/4a = 12a2+8a+4
8878
2a3 - 128 = 2*(a3 - 64) = 2*(a -4)*(a2 + 4a + 16)