idont know
64-x2 = (8-x)(8+x) when factored
6(2x - 3y)
6(u-14)
(4+x) (2x-3)
D.4(2x - 3)(2x + 1)
x(4x-2)
x2 - 2x = x(x - 2)
(2x - 1)(x + 3)
3(x - 1)( x + 8)
x2 + 7x - 56 cannot be factorised.
2(x-32)(x+60)
The expression ( n^2 - 3n - 4 ) can be factored by finding two numbers that multiply to (-4) (the constant term) and add to (-3) (the coefficient of the linear term). These numbers are (-4) and (1). Thus, the factored form is ( (n - 4)(n + 1) ).