Two x intercepts- When the discriminant is greater than zero
One x intercept- When the discriminant is equal to zero
No x intercept- When the discriminant is less than zero
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If the quadratic function is written as ax2 + bx + c, then it has no x-intercepts if the discriminant, (b2 - 4ac), is negative.
Factoring a quadratic allows you to solve the x and y intercepts. The x-intercepts in the factored form are the inverse of the constants. The y-intercept is the product of the x-intercepts multipied together. Example: x²-10x-24 = (x+2)(x-12) +2 and -12 are the constants. So ur x-intercepts are (-2,0) (12,0). The y intercept is -24 because -2 X 12 = -24.
The quadratic (parabola) intercepts the x-axis when y = 0. So substitute y=0 into y = f(x). Then you can solve for the x-values by any number of ways: Factoring, completing the square, or Quadratic Formula. It may turn out that the values of x which satisfies y=0 are complex {have an imaginary component}, which will tell you that the parabola does not have an x-intercept.
There are no intercepts because the curve, xy = 4 is asymptotic. When x = 0 (where the y intercept would be) y is infinite, and conversely, when y = 0 x is infinite.
Use the quadratic equation. If ax+bx+c=0 x=(-b±(b^2-4ac)^(1/2))/2a. You could also complete the square, factor,or graph the equation.