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How would you use intercepts to find the vertex in a quadratic equation with two x intercepts?
Wiki User
∙ 14y ago
The vertex must be half way between the two x intercepts
Wiki User
∙ 14y ago
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What is the difference between a linear function and a quadratic equation?
A linear equation describes a line like 2x+1=y. If you were to graph that equation, then it would give you a line. A quadratic equation is like x^2+2x+1=y. Graphing this equation would give you a U shaped graph called a parabola.
Would the cross section of a satellite dish be modeled by a linear or a quadratic equation?
The satellite dish is a parabolic reflector. A parabola cannot be modeled by a linear equation because a linear equation is one that graphs as a straight line. It takes a second degree expression to plot it, and that means a quadratic equation.
What would be the most logical first step to solve this quadratic equation?
take the square root of both sides.
How could the quadratic equation be used in technology?
As one example, the quadratic equation can be used to model many different phenomena - if you were to measure the height of a baseball as it was thrown straight up in the air and pulled down again, and plot the height with respect to time, it would look like a quadratic equation. Computer modelling is a large field with many applications in physics, meterology, and even social sciences.
How do I put the quadratic formula into a calculator?
The quadratic formula is x=-b±√b^2-4ac divided by 2a. You can only use this formula to solve the quadratic equation: ax^2+bx+c=0 If you were to punch the quadratic formula in the calculator, you would have to punch in the formula except replace the variables with the numbers from the equation. Ex. x^2+2x+1=0 a=1; b=2; c=1 In the calculator you would punch in x=-2±√2^2-4(1)(1) Or simply the equation without x=
What is the quadratic equation used for?
It is used to solve quadratic equations that cannot be factored. Usually you would factor a quadratic equation, identify the critical values and solve, but when you cannot factor you utilize the quadratic equation.
What are the four steps for solving a quadratic equation?
The 1st step would have been to show a particular quadratic equation in question.
What the Vertex form of a quadratic equations?
The vertex form of a quatdratic equation (otherwise called the graphing form) is y=a(x-h)2+k For those of you who don't know what 'h', 'a', and 'k' are, they are parameters. The negative sign in front of the 'h' refers to the opposite of the x coordinate in the vertex. The 'k' refers to the y coordinate in the vertex. 'A' refers to the stretch or compression factor. So, for example, say you have a parabola with a stretch factor of 2 whose vertex coordinates are (-3,4). The equation would be y=2(x+3)2+4 Of course, if a parabola has no stretch/compression factor, there would be no 'a' in the equation. I hope this helped, and good luck!
What is the parabola equation?
the equation of a parabola is: y = a(x-h)^2 + k *h and k are the x and y intercepts of the vertex respectively * x and y are the coordinates of a known point the curve passes though * solve for a, then plug that a value back into the equation of the parabola with out the coordinates of the known point so the equation of the curve with the vertex at (0,3) passing through the point (9,0) would be.. 0 = a (9-0)^2 + 3 = 0 = a (81) + 3 = -3/81 = a so the equation for the curve would be y = -(3/81)x^2 + 3
How would you go about solving a quadratic equation?
Write the quadratic equation in the form ax2 + bx + c = 0 then the roots (solutions) of the equation are: [-b ± √(b2 - 4*a*c)]/(2*a)
The quadratic term in 6x2 - 4x plus 25 is 6x2?
the equation 6x^2 - 4x + 25 is a quadratic equation due to the 6x^2 term. Whatever number on the x squared term changes it to a quadratic equation if you were to get rid of the 6x^2 then the equation would simply be -4x+25 making it simply a linear equation. when ever you have an x raised to 2 that term is the quadratic term in the equation.
How is the St. Louis Arch an example of a Quadratic Function?
The St. Louis Arch is in the shape of a hyperbolic cosine function It is often thought that it is in the shape of a parabola, which would have a quadratic function of y = a(x-h)^2 + k, where the vertex is h, k.
What would be the project about quadratic equation?
it shld be on completing d square,,,
What are the solutions to the equation 2x2 plus 3x-50?
Without an equality sign the given quadratic expression can't be classed as an equation but knowing how to use the quadratic equation formula would be helpful when given such problems.
Is y equals x2 plus 4 a linear equation?
It is linear in y, quadratic in x. Generally, that would be considered a quadratic.
What is the difference between a linear function and a quadratic equation?
A linear equation describes a line like 2x+1=y. If you were to graph that equation, then it would give you a line. A quadratic equation is like x^2+2x+1=y. Graphing this equation would give you a U shaped graph called a parabola.
How do you create a function to calculate the roots of any given quadratic equation?
First rewrite the quadratic equation in the form: ax2 + bx + c = 0 where a , b and c are constant coefficients. Clearly, a is not = 0 for if it were then you would have a linear equation and not a quadratic. Then the roots of the quadratic are: x = [-b +/- sqrt(b2 - 4ac)]/2a where using the + and - values of the square root result in two solutions.
