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A = L2

if you double the sides, the area will be 4 times larger than the original one.

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Q: When you double the sides of the square how does the area of the larger square change?
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Why does the area become 4 times larger than the original one when you double the sides of a square?

Area of a square = side2. When you multiply the side times 2, you have to square it to get the area. 22 =4

What is the ratio of corresponding sides of two similar triangles whose areas are 36 square inches and 144 square inches?

Areas are proportional to the square of corresponding sides. Therefore, in this case: * Divide 144 by 36. * Take the square root of the result. That will give you the ratio of the corresponding sides.

What is a double square pyramid?

a double square pymid is a shape with at least more than eight sides. it is calld a double square prymid beacuse the shape is double the sizs

How much larger is the side of a square circumscribing a circle 155 cm indiameter than a square inscribed in the same circle?

The circumscribing square has sides of length 155 cm. The inscribed square has diagonals of 155 cm and so has sides of 155/sqrt(2) cm. The sides of a circumscribing square is always larger than those of the inscribed square by sqrt(2) = 1.4142 (approx). The area of a circumscribing square is always larger twice as large as that of the inscribed square.

What happens to the side length of a square when you double the area?

To double the area of a square, you must multiply the length of the sides by the square root of 2, √2, which is about 1.414.

How does the area of a rectangle change when its dimensions change?

the area should double also Answer 2 The area will quadruple. Imagine a square with sides 1 x 1. If you doubled the length of the sides you'd have a square of 2 x 2. You'd be able to get four 1 x 1 squares inside that.

What do you do to change a square into a polygon Do you extent all sides or not?

It seems to us that you don't have to do anything, because a square is already a polygon. Extending the sides of a square just gives you a bigger square.

How is 4 the maximum number of nonoverlapping squares with sides of length 3 that will fit inside of a square with sides of length 6?

Each of the four squares, combined, must have a perimeterwhich adds up to that of the larger square. Since the larger square has a perimeter of 24, so must these squares. However, since we are placing them next to each other, the 2 sides of each square facing other sides do not count. Each individual square has a perimeter of 12, so that makes 48. Subtracting the lengths of the sides placed adjacent to each other (8 sides x a length of 3 = 24), we get a perimeter of 24, the perimeter of the larger square. Because the perimeters are equal, there is no room left for another square without overlapping.

Which of these two regular polygon has the larger interior angle?

square or octagon

Does doubling the side length of a square double the area?

No. If you double the length of the sides, you multiply the area by 4. For example, a 10x10 square has an area of 100, but a 20x20 square has an area of 400.

What would you have to change in a rhombus to make it a square?

all sides must be equal so you increase the sides

What happens to the area of a square when you double its sides?

The area will increase by a factor of 4 in this case.