As soon as you let go of the coin, there will be no upwards force acting on the coin and so no upward acceleration. There will be downwards acceleration due to the force of the earth's gravity.
If you want to be more accurate you could include aerodynamic drag which will operate in the direction opposite to that of the motion.
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If it is a fair coin then 50/50 or 1 chance in 2. The coin has no memory of the tosses that went before.
This depends on what the graph represents. If it is a graph of velocity on the vertical and time on the horizontal, then if acceleration is at a constant rate, the graph will be a straight line with positive slope (pointing 'up'). If acceleration stops, then the graph will be a horizontal line (zero acceleration or deceleration). If it is deceleration (negative acceleration), then the graph will have negative slope (pointing down).
The answer depends on how many times the coin is tossed. The probability is zero if the coin is tossed only once! Making some assumptions and rewording your question as "If I toss a fair coin twice, what is the probability it comes up heads both times" then the probability of it being heads on any given toss is 0.5, and the probability of it being heads on both tosses is 0.5 x 0.5 = 0.25. If you toss it three times and want to know what the probability of it being heads exactly twice is, then the calculation is more complicated, but it comes out to 0.375.
Normally there would considered to be 2⁴ = 16 possible outcomes as each outcome is one of 2 states: Head or Tails. ------------------------- There is an extremely small probability that a normal coin will end up on its edge, which mean there are 3⁴ = 81 possible outcomes. However, this probability is so small that it is ignored and normally only 2 outcomes are considered possible. As the radius to width ratio of the coin changes, the probability of the coin ending up on its edge changes, for some values being so significant that it becomes a real probability that the edge can result, and for some ratios it is almost always the edge that results and the probability of head or tails (ie ends of the cylinder that is the coin) is so small as to be ignored like the edge for a normal sized coin (cylinder).
4m/s Acceleration = velocity change / time = (9m/s - 5m/s) / 4 sec A = (9-5) / 4 = 1 m/s2.