Normally there would considered to be 2⁴ = 16 possible outcomes as each outcome is one of 2 states: Head or Tails.
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There is an extremely small probability that a normal coin will end up on its edge, which mean there are 3⁴ = 81 possible outcomes. However, this probability is so small that it is ignored and normally only 2 outcomes are considered possible. As the radius to width ratio of the coin changes, the probability of the coin ending up on its edge changes, for some values being so significant that it becomes a real probability that the edge can result, and for some ratios it is almost always the edge that results and the probability of head or tails (ie ends of the cylinder that is the coin) is so small as to be ignored like the edge for a normal sized coin (cylinder).
Each toss has 2 outcomes; so the number of outcomes for 3 tosses is 2*2*2 = 8
Assuming the coins are fair, two-sided coins, and landing on their sides is not an option, there are four possible outcomes if you consider coin a having a head and coin b having a tail being a different instance from coin a being a tail and coin be having a head. Here they are; Coin A | Coin B Heads | Tails Heads | Heads Tails....| Heads Tails....| Tails
6 outcomes for each die and so 6x6x6 outcomes for all three
In tossing a coin, there are two outcomes; head or tail. Since there are two outcomes, probability of each outcome is: 0.5. Assuming a fair coin, probability of a head or tail is: 0.5. So, probability a team will win a toss is: 0.5.
7/8
the outcomes are 50:50.
Each toss has 2 outcomes; so the number of outcomes for 3 tosses is 2*2*2 = 8
Heads or tails; each have a probability of 0.5 (assuming a fair coin).
3 of them.
The probability of getting heads only once when a fair coin is tossed 4 times is 4/16 or 0.25. This is because there are 4 favorable outcomes where heads appears exactly once, out of the 16 possible outcomes.
In three flips of a fair coin, there are a total of 8 possible outcomes: T, T, T; T, T, H; T, H, T; T, H, H; H, H, H; H, H, T; H, T, H; H, T, T Of the possible outcomes, four of them (half) contain at least two heads, as can be seen by inspection. Note: In flipping a coin, there are two possible outcomes at each flipping event. The number of possible outcomes expands as a function of the number of times the coin is flipped. One flip, two possible outcomes. Two flips, four possible outcomes. Three flips, eight possible outcomes. Four flips, sixteen possible outcomes. It appears that the number of possible outcomes is a power of the number of possible outcomes, which is two. 21 = 2, 22 = 4, 23 = 8, 24 = 16, .... Looks like a pattern developing there. Welcome to this variant of permutations.
A probability is fair if there is no bias in any of the possible outcomes. Said another way, all of the possible outcomes in a fair distribution have an equal probability.
Assuming the coins are fair, two-sided coins, and landing on their sides is not an option, there are four possible outcomes if you consider coin a having a head and coin b having a tail being a different instance from coin a being a tail and coin be having a head. Here they are; Coin A | Coin B Heads | Tails Heads | Heads Tails....| Heads Tails....| Tails
It is possible. It is certain with a double headed coin. With a fair coin the event has a probability of 1 in 1048576 or approximately 1 in a million.
130 instances of 3 heads out of 1024 total possible outcomes=130/1024=0.126953125
If you know which coin is which, there are 16possible outcomes.If you're only counting the number of Heads and Tails, there are 5 .
Since it is a fair coin, the probability is 0.5