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( m^2 - m - 3 ) + ( m - 4 ) = m^2 - m - 3 + m - 4 = m^2 - 7Answer: m^2 - 7
m-15=3 m-15+15=3+15 m=3+15 m=18
m + 3 - 20 = 5 m + 3 = 25 m = 22
Assuming that you meant that the equation is y=3x+1, the slope is 3. This is because the equation of any line in the form of y=mx+b has a slope of "m". Therefore, the value of m in this equation is 3.
3 m and 2 m are two measures. For a volume, 3 dimensional measures are required.
s, o, n (the months of the year)
3000
From the Steam Tables I get the following: T v sub f d ( kg / m^3 ] 15.0 C 0.001001 m^3/ kg 999.0 kg / m^3 20.0 C 0.001002 m^3/ kg 998.0 kg/ m^3 25.0 C 0.001003 m^3 / kg 1001 kg / L^3 30.0 C 0 .001004 m^3 / kg 996.0 kg/m^3 -------------------- Search also NISTIR 6969, table 9.8 (it's free on Internet) or a density calculator.
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Length: meter (m) Volume: cubic meter (m^3) Mass: kilogram (kg)
R All other brackets all have 3 steps between a letter to the next.
If you are following y= mx+b m would be (-3) so y=-3x+5 would be good or -3y=x-2 or any one that when simplified has a value of -3 next to x
To find the rate of the reaction following the rate law rate = k[A]^m[B]^n, we substitute the values given: ( k = 0.2 , \text{M}^{-2} , \text{s}^{-1} ), ( [A] = 3 , \text{M} ), and ( [B] = 3 , \text{M} ) with ( m = 2 ) and ( n = 3 ). The rate can be calculated as follows: [ \text{Rate} = 0.2 \cdot (3)^2 \cdot (3)^3 = 0.2 \cdot 9 \cdot 27 = 48.6 , \text{M/s}. ] Thus, the rate of the reaction is 48.6 M/s.
( m^2 - m - 3 ) + ( m - 4 ) = m^2 - m - 3 + m - 4 = m^2 - 7Answer: m^2 - 7
m-15=3 m-15+15=3+15 m=3+15 m=18
m=y2-y1/x2-x1 m=-1- 3/3-(-3) m=-4/6 m=-2/3
The letters represent the initials of the months: January, February, March, etc. That being so, the next 3 letters would be SON (Sept, Oct, Nov).