There are infinitely many sets.
Restricting the answers to positive integers, you can have
1, 1, 12, 13, 23;
1, 1, 12, 14, 22;
1, 1, 12, 15, 21;
and so on until
1, 1, 12, 18, 18.
Then you go to 1, 2, 12, 13, 22 and so on.
Perhaps you can now see that there are very many possible solutions. And the number of solutions increases if negative integers are permitted. And increases to infinitely many if real numbers are permitted instead of only integers.
8, 9, 11 and 12
Mean: 37.2 Median: 20 Mode: 20, 12, 61, 74, 19
As there are 6 numbers, the median is half way between the middle numbers, or (7+9) / 2 = 8
14
median = 11.5 mean = 12
8, 9, 11 and 12
Mean: 20.2222222 Median: 12 Mode: 11 Range: 79
There is no single answer to that. You could come up with many sets of numbers that would have those properties.
mean = 19 median = 12 mode = 12
Mean = 14 Median = 12 Mode = 12
10 numbers in the sample. Middle numbers are 10 and 14. Then the median is (10+14)/2=12
There are 6 numbers, so the median is the mean of the middle two: (7 + 8) ÷ 2 = 7.5
The median of the numbers 10 12 13 17 17 18 27 is 17.
7
yes, for instance if you have numbers: -15 -12 -10 -9 -5, then the median would me -10
List the numbers in order. If there is an ODD number of numbers, the median is the number in the middle (eg if there are 11 numbers listed, the median is the (11+1)÷2 = 6th number). If there is an EVEN number of numbers, the median is the mean of the middle two (eg if there are 12 numbers listed, the median is the mean of the (12÷2) = 6th and the 6th+1 = 7th numbers, ie (6th+7th)÷2.)
Mean: 11.6 Median: 12 Mode: 10, 12, 15, 16, 5 Range: 11